#1
TOP-1
0.36 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.36 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.36 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.36 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.36 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.36 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.36 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.36 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.36 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.23 ± 0.13
CC(C)[n+]1ccn2C3=[N](->[Ru+2]<-[c-]21)C1C=CC=CC1S3
#1
TOP-1
0.00 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]3(<-[c-]4n(C5=[N]->3C3C=CC=CC3S5)cc[n+]4C(C)C)<-[cH]12
#2
0.20 ± 0.00
CC(C)[n+]1ccn2C3=[N](->[Ru+2]<-[c-]21)C1C=CC=CC1S3
#2
0.20 ± 0.00
CC(C)[n+]1ccn2C3=[N](->[Ru+2]<-[c-]21)C1C=CC=CC1S3
#2
0.20 ± 0.00
CC(C)[n+]1ccn2C3=[N](->[Ru+2]<-[c-]21)C1C=CC=CC1S3
#2
0.20 ± 0.00
CC(C)[n+]1ccn2C3=[N](->[Ru+2]<-[c-]21)C1C=CC=CC1S3
#2
0.20 ± 0.00
CC(C)[n+]1ccn2C3=[N](->[Ru+2]<-[c-]21)C1C=CC=CC1S3
#2
0.20 ± 0.00
CC(C)[n+]1ccn2C3=[N](->[Ru+2]<-[c-]21)C1C=CC=CC1S3
#2
0.20 ± 0.00
CC(C)[n+]1ccn2C3=[N](->[Ru+2]<-[c-]21)C1C=CC=CC1S3
#2
0.20 ± 0.00
CC(C)[n+]1ccn2C3=[N](->[Ru+2]<-[c-]21)C1C=CC=CC1S3
#2
0.20 ± 0.00
CC(C)[n+]1ccn2C3=[N](->[Ru+2]<-[c-]21)C1C=CC=CC1S3
#2
0.00 ± 0.00
CC(C)[n+]1ccn(C2=NC3C=CC=CC3S2)[c-]1->[Ru+2]
#2
0.00 ± 0.00
CC(C)[n+]1ccn2C3=[N](->[Ru+2]45678(<-[c-]21)<-[cH]1[cH]->4[c]->5(C(C)C)[cH]->6[cH]->7[c]->81C)C1C=CC...
#3
0.08 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#3
0.08 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#3
0.08 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#3
0.08 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#3
0.08 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#3
0.08 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#3
0.08 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#3
0.08 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12