12
Candidates
{"N": 6}
Ground Truth
{"N": 2}
Top-1 Prediction
0.990
Match Score
#1
TOP-1
0.99 ± 0.00
O=C1C(=O)c2ccc[n]3->[Ru+2]<-[n]4cccc1c4-c23
#2
0.38 ± 0.31
c1cnc2c(c1)C1=[O]->[Ru+2]<-[O]=C1c1cccnc1-2
#3
0.04 ± 0.06
O=C1C(=O)c2ccc[n](->[Ru+2])c2-c2ncccc21
#4
0.00 ± 0.00
O=C1c2cccnc2-c2ncccc2[C]12[O][Ru+2]2
#5
0.00 ± 0.00
O=C1C(=O)c2c3nc[cH]4->[Ru+2](<-[cH]24)<-[n]2cccc1c2-3
#6
0.00 ± 0.00
O=C1C(=[O]->[Ru+2])c2cccnc2-c2ncccc21
#7
0.00 ± 0.00
O=C1C(=O)c2c(nc[cH]3->[Ru+2]<-[cH]23)-c2ncccc21
#8
0.00 ± 0.00
O=C1C(=O)c2cccnc2C2=C1[CH]1[Ru+2][CH]1C=N2
#9
0.00 ± 0.00
O=C1C(=O)c2c3nc[cH]4->[Ru+2](<-[cH]5ccnc-3c51)<-[cH]24
#10
0.00 ± 0.00
O=C1C(=O)c2c3nc[cH]4->[Ru+2](<-[cH]5cnc-3c1c5)<-[cH]24
#11
0.00 ± 0.00
O=C1C(=O)c2c[cH](->[Ru+2])cnc2-c2ncccc21
#12
0.00 ± 0.00
O=C1C(=O)c2c(ncc[cH]2->[Ru+2])-c2ncccc21