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Complex #967 — Ru(2) [[Ru(bpy)2L]Cl2]

GT: {"N": 6} → Top-1: {"N": 12}
rdmetallics.net (363)Sequential multi-lig (7058)Single-ligand (939)
3
Candidates
{"N": 6}
Ground Truth
{"N": 12}
Top-1 Prediction
0.500
Match Score
⬇ MOL (coordinated) Raw MOL 🔬 3D Viewer Complex detail
⚠ Per-candidate scores unavailable for sequential. Showing 30 candidates from single-ligand scoring. For sequential results only top-1 prediction is stored.
#1 TOP-1 1.00 ± 0.00
O=C1C(=O)c2ccc[n]3->[Ru+2]<-[n]4cccc1c4-c23
#1 TOP-1 1.00 ± 0.00
O=C1C(=O)c2ccc[n]3->[Ru+2]<-[n]4cccc1c4-c23
#1 TOP-1 1.00 ± 0.00
O=C1C(=O)c2ccc[n]3->[Ru+2]<-[n]4cccc1c4-c23
#1 TOP-1 1.00 ± 0.00
O=C1C(=O)c2ccc[n]3->[Ru+2]<-[n]4cccc1c4-c23
#1 TOP-1 1.00 ± 0.00
O=C1C(=O)c2ccc[n]3->[Ru+2]<-[n]4cccc1c4-c23
#1 TOP-1 1.00 ± 0.00
O=C1C(=O)c2ccc[n]3->[Ru+2]<-[n]4cccc1c4-c23
#1 TOP-1 1.00 ± 0.00
O=C1C(=O)c2ccc[n]3->[Ru+2]<-[n]4cccc1c4-c23
#1 TOP-1 1.00 ± 0.00
O=C1C(=O)c2ccc[n]3->[Ru+2]<-[n]4cccc1c4-c23
#1 TOP-1 0.99 ± 0.00
O=C1C(=O)c2ccc[n]3->[Ru+2]<-[n]4cccc1c4-c23
#2 0.99 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+2]<-1
#2 0.99 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+2]<-1
#2 0.99 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+2]<-1
#2 0.99 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+2]<-1
#2 0.99 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+2]<-1
#2 0.99 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+2]<-1
#2 0.99 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+2]<-1
#2 0.99 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+2]<-1
#2 0.38 ± 0.31
c1cnc2c(c1)C1=[O]->[Ru+2]<-[O]=C1c1cccnc1-2
#3 0.97 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+]<-1
#3 0.97 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+]<-1
#3 0.97 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+]<-1
#3 0.97 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+]<-1
#3 0.97 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+]<-1
#3 0.97 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+]<-1
#3 0.97 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+]<-1
#3 0.97 ± 0.00
CCCCCCCCCCCCCCCCCC[NH]1Cc2cccc[n]2->[Ru+]<-1
#3 0.04 ± 0.06
O=C1C(=O)c2ccc[n](->[Ru+2])c2-c2ncccc21
#4 0.25 ± 0.00
c1cnc2c(c1)C1=[O]->[Ru+2]<-[O]=C1c1cccnc1-2
#4 0.25 ± 0.00
c1cnc2c(c1)C1=[O]->[Ru+2]<-[O]=C1c1cccnc1-2
#4 0.25 ± 0.00
c1cnc2c(c1)C1=[O]->[Ru+2]<-[O]=C1c1cccnc1-2