#1
TOP-1
0.69 ± 0.00
c1ccc([P]2(CCCC[P](->[Ru+2]<-2)(c2ccccc2)c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.69 ± 0.00
c1ccc([P]2(CCCC[P](->[Ru+2]<-2)(c2ccccc2)c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.69 ± 0.00
c1ccc([P]2(CCCC[P](->[Ru+2]<-2)(c2ccccc2)c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.69 ± 0.00
c1ccc([P]2(CCCC[P](->[Ru+2]<-2)(c2ccccc2)c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.69 ± 0.00
c1ccc([P]2(CCCC[P](->[Ru+2]<-2)(c2ccccc2)c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.69 ± 0.00
c1ccc([P]2(CCCC[P](->[Ru+2]<-2)(c2ccccc2)c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.69 ± 0.00
c1ccc([P]2(CCCC[P](->[Ru+2]<-2)(c2ccccc2)c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.69 ± 0.00
c1ccc([P]2(CCCC[P](->[Ru+2]<-2)(c2ccccc2)c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.69 ± 0.00
c1ccc([P]2(CCCC[P](->[Ru+2]<-2)(c2ccccc2)c2ccccc2)c2ccccc2)cc1
#2
0.32 ± 0.00
Clc1ccc(/C=C/C2[O][Ru+]<-[O]=2)cc1
#2
0.32 ± 0.00
Clc1ccc(/C=C/C2[O][Ru+]<-[O]=2)cc1
#2
0.32 ± 0.00
Clc1ccc(/C=C/C2[O][Ru+]<-[O]=2)cc1
#2
0.32 ± 0.00
Clc1ccc(/C=C/C2[O][Ru+]<-[O]=2)cc1
#2
0.32 ± 0.00
Clc1ccc(/C=C/C2[O][Ru+]<-[O]=2)cc1
#2
0.32 ± 0.00
Clc1ccc(/C=C/C2[O][Ru+]<-[O]=2)cc1
#2
0.32 ± 0.00
Clc1ccc(/C=C/C2[O][Ru+]<-[O]=2)cc1
#2
0.32 ± 0.00
Clc1ccc(/C=C/C2[O][Ru+]<-[O]=2)cc1
#2
0.32 ± 0.00
Clc1ccc(/C=C/C2[O][Ru+]<-[O]=2)cc1
#3
0.07 ± 0.00
c1ccc(P(CCCC[P](c2ccccc2)(c2ccccc2)->[Ru+2]2<-[n]3ccccc3-c3cccc[n]->23)c2ccccc2)cc1
#3
0.07 ± 0.00
c1ccc(P(CCCC[P](c2ccccc2)(c2ccccc2)->[Ru+2]2<-[n]3ccccc3-c3cccc[n]->23)c2ccccc2)cc1
#3
0.07 ± 0.00
c1ccc(P(CCCC[P](c2ccccc2)(c2ccccc2)->[Ru+2]2<-[n]3ccccc3-c3cccc[n]->23)c2ccccc2)cc1
#3
0.07 ± 0.00
c1ccc(P(CCCC[P](c2ccccc2)(c2ccccc2)->[Ru+2]2<-[n]3ccccc3-c3cccc[n]->23)c2ccccc2)cc1
#3
0.07 ± 0.00
c1ccc(P(CCCC[P](c2ccccc2)(c2ccccc2)->[Ru+2]2<-[n]3ccccc3-c3cccc[n]->23)c2ccccc2)cc1
#3
0.07 ± 0.00
c1ccc(P(CCCC[P](c2ccccc2)(c2ccccc2)->[Ru+2]2<-[n]3ccccc3-c3cccc[n]->23)c2ccccc2)cc1
#3
0.07 ± 0.00
c1ccc(P(CCCC[P](c2ccccc2)(c2ccccc2)->[Ru+2]2<-[n]3ccccc3-c3cccc[n]->23)c2ccccc2)cc1
#3
0.07 ± 0.00
c1ccc(P(CCCC[P](c2ccccc2)(c2ccccc2)->[Ru+2]2<-[n]3ccccc3-c3cccc[n]->23)c2ccccc2)cc1
#3
0.07 ± 0.00
c1ccc(P(CCCC[P](c2ccccc2)(c2ccccc2)->[Ru+2]2<-[n]3ccccc3-c3cccc[n]->23)c2ccccc2)cc1
#4
0.05 ± 0.00
[Ru+2]<-[P](CCCCP(c1ccccc1)c1ccccc1)(c1ccccc1)c1ccccc1
#4
0.05 ± 0.00
[Ru+2]<-[P](CCCCP(c1ccccc1)c1ccccc1)(c1ccccc1)c1ccccc1
#4
0.05 ± 0.00
[Ru+2]<-[P](CCCCP(c1ccccc1)c1ccccc1)(c1ccccc1)c1ccccc1