#1
TOP-1
0.09 ± 0.00
c1ccc(-c2n[n]3->[Ru+2]4<-[n]5ccccc5-c3n[n]->42)cc1
#1
TOP-1
0.09 ± 0.00
c1ccc(-c2n[n]3->[Ru+2]4<-[n]5ccccc5-c3n[n]->42)cc1
#1
TOP-1
0.09 ± 0.00
c1ccc(-c2n[n]3->[Ru+2]4<-[n]5ccccc5-c3n[n]->42)cc1
#1
TOP-1
0.09 ± 0.00
c1ccc(-c2n[n]3->[Ru+2]4<-[n]5ccccc5-c3n[n]->42)cc1
#1
TOP-1
0.09 ± 0.00
c1ccc(-c2n[n]3->[Ru+2]4<-[n]5ccccc5-c3n[n]->42)cc1
#1
TOP-1
0.09 ± 0.00
c1ccc(-c2n[n]3->[Ru+2]4<-[n]5ccccc5-c3n[n]->42)cc1
#1
TOP-1
0.09 ± 0.00
c1ccc(-c2n[n]3->[Ru+2]4<-[n]5ccccc5-c3n[n]->42)cc1
#1
TOP-1
0.09 ± 0.00
c1ccc(-c2n[n]3->[Ru+2]4<-[n]5ccccc5-c3n[n]->42)cc1
#1
TOP-1
0.09 ± 0.00
c1ccc(-c2n[n]3->[Ru+2]4<-[n]5ccccc5-c3n[n]->42)cc1
#2
0.04 ± 0.00
c1ccc(-c2nnc3-c4cccc[n]4->[Ru+2](<-[n]3n2)<-[n]2c(-c3ccc4ccccc4n3)ccc3ccccc32)cc1
#2
0.04 ± 0.00
c1ccc(-c2nnc3-c4cccc[n]4->[Ru+2](<-[n]3n2)<-[n]2c(-c3ccc4ccccc4n3)ccc3ccccc32)cc1
#2
0.04 ± 0.00
c1ccc(-c2nnc3-c4cccc[n]4->[Ru+2](<-[n]3n2)<-[n]2c(-c3ccc4ccccc4n3)ccc3ccccc32)cc1
#2
0.04 ± 0.00
c1ccc(-c2nnc3-c4cccc[n]4->[Ru+2](<-[n]3n2)<-[n]2c(-c3ccc4ccccc4n3)ccc3ccccc32)cc1
#2
0.04 ± 0.00
c1ccc(-c2nnc3-c4cccc[n]4->[Ru+2](<-[n]3n2)<-[n]2c(-c3ccc4ccccc4n3)ccc3ccccc32)cc1
#2
0.04 ± 0.00
c1ccc(-c2nnc3-c4cccc[n]4->[Ru+2](<-[n]3n2)<-[n]2c(-c3ccc4ccccc4n3)ccc3ccccc32)cc1
#2
0.04 ± 0.00
c1ccc(-c2nnc3-c4cccc[n]4->[Ru+2](<-[n]3n2)<-[n]2c(-c3ccc4ccccc4n3)ccc3ccccc32)cc1
#2
0.04 ± 0.00
c1ccc(-c2nnc3-c4cccc[n]4->[Ru+2](<-[n]3n2)<-[n]2c(-c3ccc4ccccc4n3)ccc3ccccc32)cc1
#2
0.04 ± 0.00
c1ccc(-c2nnc3-c4cccc[n]4->[Ru+2](<-[n]3n2)<-[n]2c(-c3ccc4ccccc4n3)ccc3ccccc32)cc1
#3
0.00 ± 0.00
C1=NC(c2nnc(-c3ccccc3)nn2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(c2nnc(-c3ccccc3)nn2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(c2nnc(-c3ccccc3)nn2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(c2nnc(-c3ccccc3)nn2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(c2nnc(-c3ccccc3)nn2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(c2nnc(-c3ccccc3)nn2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(c2nnc(-c3ccccc3)nn2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(c2nnc(-c3ccccc3)nn2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(c2nnc(-c3ccccc3)nn2)=C[CH]2[Ru+2][CH]12
#4
0.00 ± 0.00
c1cc[n]2->[Ru+2]3<-[cH]4ccc(-c5nnc(-c2c1)nn5)c[cH]->34
#4
0.00 ± 0.00
c1cc[n]2->[Ru+2]3<-[cH]4ccc(-c5nnc(-c2c1)nn5)c[cH]->34
#4
0.00 ± 0.00
c1cc[n]2->[Ru+2]3<-[cH]4ccc(-c5nnc(-c2c1)nn5)c[cH]->34