#1
TOP-1
0.77 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru]3<-[n]4cccn4C2([O]3)c2ccccc21
#1
TOP-1
0.77 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru]3<-[n]4cccn4C2([O]3)c2ccccc21
#1
TOP-1
0.77 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru]3<-[n]4cccn4C2([O]3)c2ccccc21
#1
TOP-1
0.77 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru]3<-[n]4cccn4C2([O]3)c2ccccc21
#1
TOP-1
0.77 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru]3<-[n]4cccn4C2([O]3)c2ccccc21
#1
TOP-1
0.77 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru]3<-[n]4cccn4C2([O]3)c2ccccc21
#1
TOP-1
0.77 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru]3<-[n]4cccn4C2([O]3)c2ccccc21
#1
TOP-1
0.77 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru]3<-[n]4cccn4C2([O]3)c2ccccc21
#1
TOP-1
0.77 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru]3<-[n]4cccn4C2([O]3)c2ccccc21
#2
0.01 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru][O]C2(n2cccn2)c2ccccc21
#2
0.01 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru][O]C2(n2cccn2)c2ccccc21
#2
0.01 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru][O]C2(n2cccn2)c2ccccc21
#2
0.01 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru][O]C2(n2cccn2)c2ccccc21
#2
0.01 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru][O]C2(n2cccn2)c2ccccc21
#2
0.01 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru][O]C2(n2cccn2)c2ccccc21
#2
0.01 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru][O]C2(n2cccn2)c2ccccc21
#2
0.01 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru][O]C2(n2cccn2)c2ccccc21
#2
0.01 ± 0.00
O=C1C(CN2CCOCC2)=C2[O][Ru][O]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(CN2CCOCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(CN2CCOCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(CN2CCOCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(CN2CCOCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(CN2CCOCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(CN2CCOCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(CN2CCOCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(CN2CCOCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(CN2CCOCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#4
0.00 ± 0.00
O=C1C2C[N]3(->[Ru+2]<-[n]4cccn4C([O-])(C=2[O-])c2ccccc21)CCOCC3
#4
0.00 ± 0.00
O=C1C2C[N]3(->[Ru+2]<-[n]4cccn4C([O-])(C=2[O-])c2ccccc21)CCOCC3
#4
0.00 ± 0.00
O=C1C2C[N]3(->[Ru+2]<-[n]4cccn4C([O-])(C=2[O-])c2ccccc21)CCOCC3