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Complex #461 — Ru(2) [RuPhBio]

GT: {"N": 5} → Top-1: {"N": 3}
rdmetallics.net (363)Sequential multi-lig (7058)Single-ligand (939)
2
Candidates
{"N": 5}
Ground Truth
{"N": 3}
Top-1 Prediction
0.000
Match Score
⚠ Per-candidate scores unavailable for sequential. Showing 30 candidates from single-ligand scoring. For sequential results only top-1 prediction is stored.
#1 TOP-1 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3c(C(=O)OCCCCCCN1)cc1cccnc1c32
#1 TOP-1 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3c(C(=O)OCCCCCCN1)cc1cccnc1c32
#1 TOP-1 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3c(C(=O)OCCCCCCN1)cc1cccnc1c32
#1 TOP-1 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3c(C(=O)OCCCCCCN1)cc1cccnc1c32
#1 TOP-1 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3c(C(=O)OCCCCCCN1)cc1cccnc1c32
#1 TOP-1 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3c(C(=O)OCCCCCCN1)cc1cccnc1c32
#1 TOP-1 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3c(C(=O)OCCCCCCN1)cc1cccnc1c32
#1 TOP-1 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3c(C(=O)OCCCCCCN1)cc1cccnc1c32
#1 TOP-1 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3c(C(=O)OCCCCCCN1)cc1cccnc1c32
#2 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3cc(C(=O)OCCCCCCN1)c1cccnc1c32
#2 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3cc(C(=O)OCCCCCCN1)c1cccnc1c32
#2 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3cc(C(=O)OCCCCCCN1)c1cccnc1c32
#2 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3cc(C(=O)OCCCCCCN1)c1cccnc1c32
#2 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3cc(C(=O)OCCCCCCN1)c1cccnc1c32
#2 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3cc(C(=O)OCCCCCCN1)c1cccnc1c32
#2 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3cc(C(=O)OCCCCCCN1)c1cccnc1c32
#2 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3cc(C(=O)OCCCCCCN1)c1cccnc1c32
#2 0.00 ± 0.00
O=C1CCCC[C@H]2SC[C@@H]3[C@H]2NC(O)=[N]3->[Ru+2]<-[n]2cccc3cc(C(=O)OCCCCCCN1)c1cccnc1c32
#3 0.00 ± 0.00
O=C(CCCC[C@H]1SC[C@@H]2[C@H]1NC(O)=[N]2->[Ru+2])NCCCCCCOC(=O)c1cc2cccnc2c2ncccc12
#3 0.00 ± 0.00
O=C(CCCC[C@H]1SC[C@@H]2[C@H]1NC(O)=[N]2->[Ru+2])NCCCCCCOC(=O)c1cc2cccnc2c2ncccc12
#3 0.00 ± 0.00
O=C(CCCC[C@H]1SC[C@@H]2[C@H]1NC(O)=[N]2->[Ru+2])NCCCCCCOC(=O)c1cc2cccnc2c2ncccc12
#3 0.00 ± 0.00
O=C(CCCC[C@H]1SC[C@@H]2[C@H]1NC(O)=[N]2->[Ru+2])NCCCCCCOC(=O)c1cc2cccnc2c2ncccc12
#3 0.00 ± 0.00
O=C(CCCC[C@H]1SC[C@@H]2[C@H]1NC(O)=[N]2->[Ru+2])NCCCCCCOC(=O)c1cc2cccnc2c2ncccc12
#3 0.00 ± 0.00
O=C(CCCC[C@H]1SC[C@@H]2[C@H]1NC(O)=[N]2->[Ru+2])NCCCCCCOC(=O)c1cc2cccnc2c2ncccc12
#3 0.00 ± 0.00
O=C(CCCC[C@H]1SC[C@@H]2[C@H]1NC(O)=[N]2->[Ru+2])NCCCCCCOC(=O)c1cc2cccnc2c2ncccc12
#3 0.00 ± 0.00
O=C(CCCC[C@H]1SC[C@@H]2[C@H]1NC(O)=[N]2->[Ru+2])NCCCCCCOC(=O)c1cc2cccnc2c2ncccc12
#3 0.00 ± 0.00
O=C(CCCC[C@H]1SC[C@@H]2[C@H]1NC(O)=[N]2->[Ru+2])NCCCCCCOC(=O)c1cc2cccnc2c2ncccc12
#4 0.00 ± 0.00
O=C1CCCC[C@@H]2[C@@H]3NC(O)=N[C@@H]3C[S]2->[Ru+2]<-[n]2cccc3c(C(=O)OCCCCCCN1)cc1cccnc1c32
#4 0.00 ± 0.00
O=C1CCCC[C@@H]2[C@@H]3NC(O)=N[C@@H]3C[S]2->[Ru+2]<-[n]2cccc3c(C(=O)OCCCCCCN1)cc1cccnc1c32
#4 0.00 ± 0.00
O=C1CCCC[C@@H]2[C@@H]3NC(O)=N[C@@H]3C[S]2->[Ru+2]<-[n]2cccc3c(C(=O)OCCCCCCN1)cc1cccnc1c32