#1
TOP-1
0.32 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.32 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.32 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.32 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.32 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.32 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.32 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.32 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.32 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#2
0.29 ± 0.00
c1ccc(Cn2cc[n+]3CC[S](->[Ru+2]<-[c-]23)C23CC4CC(CC(C4)C2)C3)cc1
#2
0.29 ± 0.00
c1ccc(Cn2cc[n+]3CC[S](->[Ru+2]<-[c-]23)C23CC4CC(CC(C4)C2)C3)cc1
#2
0.29 ± 0.00
c1ccc(Cn2cc[n+]3CC[S](->[Ru+2]<-[c-]23)C23CC4CC(CC(C4)C2)C3)cc1
#2
0.29 ± 0.00
c1ccc(Cn2cc[n+]3CC[S](->[Ru+2]<-[c-]23)C23CC4CC(CC(C4)C2)C3)cc1
#2
0.29 ± 0.00
c1ccc(Cn2cc[n+]3CC[S](->[Ru+2]<-[c-]23)C23CC4CC(CC(C4)C2)C3)cc1
#2
0.29 ± 0.00
c1ccc(Cn2cc[n+]3CC[S](->[Ru+2]<-[c-]23)C23CC4CC(CC(C4)C2)C3)cc1
#2
0.29 ± 0.00
c1ccc(Cn2cc[n+]3CC[S](->[Ru+2]<-[c-]23)C23CC4CC(CC(C4)C2)C3)cc1
#2
0.29 ± 0.00
c1ccc(Cn2cc[n+]3CC[S](->[Ru+2]<-[c-]23)C23CC4CC(CC(C4)C2)C3)cc1
#2
0.29 ± 0.00
c1ccc(Cn2cc[n+]3CC[S](->[Ru+2]<-[c-]23)C23CC4CC(CC(C4)C2)C3)cc1
#3
0.10 ± 0.00
[Ru+2]<-[c-]1n(Cc2ccccc2)cc[n+]1CCSC12CC3CC(CC(C3)C1)C2
#3
0.10 ± 0.00
[Ru+2]<-[c-]1n(Cc2ccccc2)cc[n+]1CCSC12CC3CC(CC(C3)C1)C2
#3
0.10 ± 0.00
[Ru+2]<-[c-]1n(Cc2ccccc2)cc[n+]1CCSC12CC3CC(CC(C3)C1)C2
#3
0.10 ± 0.00
[Ru+2]<-[c-]1n(Cc2ccccc2)cc[n+]1CCSC12CC3CC(CC(C3)C1)C2
#3
0.10 ± 0.00
[Ru+2]<-[c-]1n(Cc2ccccc2)cc[n+]1CCSC12CC3CC(CC(C3)C1)C2
#3
0.10 ± 0.00
[Ru+2]<-[c-]1n(Cc2ccccc2)cc[n+]1CCSC12CC3CC(CC(C3)C1)C2
#3
0.10 ± 0.00
[Ru+2]<-[c-]1n(Cc2ccccc2)cc[n+]1CCSC12CC3CC(CC(C3)C1)C2
#3
0.10 ± 0.00
[Ru+2]<-[c-]1n(Cc2ccccc2)cc[n+]1CCSC12CC3CC(CC(C3)C1)C2
#3
0.10 ± 0.00
[Ru+2]<-[c-]1n(Cc2ccccc2)cc[n+]1CCSC12CC3CC(CC(C3)C1)C2
#4
0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#4
0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#4
0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12