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Complex #387 — Ru(3) [2]

GT: {"N": 4, "O": 1, "P": 2} → Top-1: {"O": 3, "N": 3, "P": 3}
rdmetallics.net (363)Sequential multi-lig (7058)Single-ligand (939)
3
Candidates
{"N": 4, "O": 1, "P": 2}
Ground Truth
{"O": 3, "N": 3, "P": 3}
Top-1 Prediction
0.600
Match Score
⚠ Per-candidate scores unavailable for sequential. Showing 30 candidates from single-ligand scoring. For sequential results only top-1 prediction is stored.
#1 TOP-1 0.03 ± 0.00
[Ru+3]<-[P](c1ccccc1)(c1ccccc1)c1ccccc1
#1 TOP-1 0.03 ± 0.00
[Ru+3]<-[P](c1ccccc1)(c1ccccc1)c1ccccc1
#1 TOP-1 0.03 ± 0.00
[Ru+3]<-[P](c1ccccc1)(c1ccccc1)c1ccccc1
#1 TOP-1 0.03 ± 0.00
[Ru+3]<-[P](c1ccccc1)(c1ccccc1)c1ccccc1
#1 TOP-1 0.03 ± 0.00
[Ru+3]<-[P](c1ccccc1)(c1ccccc1)c1ccccc1
#1 TOP-1 0.03 ± 0.00
[Ru+3]<-[P](c1ccccc1)(c1ccccc1)c1ccccc1
#1 TOP-1 0.03 ± 0.00
[Ru+3]<-[P](c1ccccc1)(c1ccccc1)c1ccccc1
#1 TOP-1 0.03 ± 0.00
[Ru+3]<-[P](c1ccccc1)(c1ccccc1)c1ccccc1
#1 TOP-1 0.03 ± 0.00
[Ru+3]<-[P](c1ccccc1)(c1ccccc1)c1ccccc1
#2 0.00 ± 0.00
O=c1[nH]cc(/C=N\N=C(/[O][Ru+2](<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)c...
#2 0.00 ± 0.00
O=c1[nH]cc(/C=N\N=C(/[O][Ru+2](<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)c...
#2 0.00 ± 0.00
O=c1[nH]cc(/C=N\N=C(/[O][Ru+2](<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)c...
#2 0.00 ± 0.00
O=c1[nH]cc(/C=N\N=C(/[O][Ru+2](<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)c...
#2 0.00 ± 0.00
O=c1[nH]cc(/C=N\N=C(/[O][Ru+2](<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)c...
#2 0.00 ± 0.00
O=c1[nH]cc(/C=N\N=C(/[O][Ru+2](<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)c...
#2 0.00 ± 0.00
O=c1[nH]cc(/C=N\N=C(/[O][Ru+2](<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)c...
#2 0.00 ± 0.00
O=c1[nH]cc(/C=N\N=C(/[O][Ru+2](<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)c...
#2 0.00 ± 0.00
O=c1[nH]cc(/C=N\N=C(/[O][Ru+2](<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)c...
#3 0.00 ± 0.00
O=c1[nH]cc(/C=[N]2->[Ru+3]<-[N]/2=C(/[O-])c2cccs2)c(=O)[nH]1
#3 0.00 ± 0.00
O=c1[nH]cc(/C=[N]2->[Ru+3]<-[N]/2=C(/[O-])c2cccs2)c(=O)[nH]1
#3 0.00 ± 0.00
O=c1[nH]cc(/C=[N]2->[Ru+3]<-[N]/2=C(/[O-])c2cccs2)c(=O)[nH]1
#3 0.00 ± 0.00
O=c1[nH]cc(/C=[N]2->[Ru+3]<-[N]/2=C(/[O-])c2cccs2)c(=O)[nH]1
#3 0.00 ± 0.00
O=c1[nH]cc(/C=[N]2->[Ru+3]<-[N]/2=C(/[O-])c2cccs2)c(=O)[nH]1
#3 0.00 ± 0.00
O=c1[nH]cc(/C=[N]2->[Ru+3]<-[N]/2=C(/[O-])c2cccs2)c(=O)[nH]1
#3 0.00 ± 0.00
O=c1[nH]cc(/C=[N]2->[Ru+3]<-[N]/2=C(/[O-])c2cccs2)c(=O)[nH]1
#3 0.00 ± 0.00
O=c1[nH]cc(/C=[N]2->[Ru+3]<-[N]/2=C(/[O-])c2cccs2)c(=O)[nH]1
#3 0.00 ± 0.00
O=c1[nH]cc(/C=[N]2->[Ru+3]<-[N]/2=C(/[O-])c2cccs2)c(=O)[nH]1
#4 0.00 ± 0.00
O=c1[nH]cc(/C=[N](->[Ru+3])\N=C(/[O-])c2cccs2)c(=O)[nH]1
#4 0.00 ± 0.00
O=c1[nH]cc(/C=[N](->[Ru+3])\N=C(/[O-])c2cccs2)c(=O)[nH]1
#4 0.00 ± 0.00
O=c1[nH]cc(/C=[N](->[Ru+3])\N=C(/[O-])c2cccs2)c(=O)[nH]1