25
Candidates
{"N": 3}
Ground Truth
{"N": 2}
Top-1 Prediction
0.990
Match Score
#1
TOP-1
0.99 ± 0.01
Cc1cc([N]2=Cc3cccc[n]3->[Ru+2]<-2)ncc1Br
#1
TOP-1
0.02 ± 0.04
Cc1cc([N]2=Cc3cccc[n]3->[Ru+2]<-234567<-[cH]2[cH]->3[c]->4(C(C)C)[cH]->5[cH]->6[c]->72C)ncc1Br
#2
0.00 ± 0.00
Cc1cc2N=Cc3cccc[n]3->[Ru+2]<-[n]2cc1Br
#2
0.00 ± 0.01
Cc1cc([N]2=Cc3cccc[n]3->[Ru+2]<-23<-[cH]2c(C)ccc(C(C)C)[cH]->32)ncc1Br
#3
0.00 ± 0.00
Cc1cc2[N](=Cc3ccccn3)->[Ru+2]<-[n]2cc1Br
#3
0.00 ± 0.00
Cc1ccc(C(C)C)[cH](->[Ru+2]2<-[N](=Cc3cccc[n]->23)c2cc(C)c(Br)cn2)c1
#4
0.00 ± 0.00
Cc1cc([N]2[Ru+2][CH]2c2ccccn2)ncc1Br
#4
0.00 ± 0.00
Cc1cc([N]2=Cc3cccc[n]3->[Ru+2]<-2<-[cH]2cc(C(C)C)ccc2C)ncc1Br
#5
0.00 ± 0.00
Cc1cc(N=Cc2ccccn2)[n](->[Ru+2])cc1Br
#6
0.00 ± 0.00
Cc1cc(N=Cc2cccc[n]2->[Ru+2])ncc1Br
#7
0.00 ± 0.00
Cc1cc([N]2=Cc3nccc[cH]3->[Ru+2]<-2)ncc1Br
#8
0.00 ± 0.00
Cc1cc(N=C[c]23->[Ru+2]<-[n]2cccc3)ncc1Br
#9
0.00 ± 0.00
Cc1cc2N=Cc3ncc[cH]4->[Ru+2](<-[cH]34)<-[n]2cc1Br
#10
0.00 ± 0.00
Cc1cc([N](->[Ru+2])=Cc2ccccn2)ncc1Br
#11
0.00 ± 0.00
Cc1cc2N=Cc3c[cH]4->[Ru+2](<-[cH]4cn3)<-[n]2cc1Br
#12
0.00 ± 0.00
Cc1cc(N=CC2=C[CH]3[Ru+2][CH]3C=N2)ncc1Br
#13
0.00 ± 0.00
Cc1cc(N=Cc2c[cH]3->[Ru+2]<-[cH]3cn2)ncc1Br
#14
0.00 ± 0.00
Cc1cc(N=Cc2ncc[cH]3->[Ru+2]<-[cH]23)ncc1Br
#15
0.00 ± 0.00
Cc1cc(N=Cc2nc[cH]3->[Ru+]4<-[cH]2[cH]->43)ncc1Br
#16
0.00 ± 0.00
Cc1c(Br)cnc2N=Cc3ncc[cH]4->[Ru+2](<-[cH]21)<-[cH]34
#17
0.00 ± 0.00
Cc1c(Br)cnc2N=Cc3c[cH]4->[Ru+2](<-[cH]21)<-[cH]4cn3
#18
0.00 ± 0.00
Cc1cc(N=Cc2cc[cH](->[Ru+2])cn2)ncc1Br
#19
0.00 ± 0.00
Cc1cc(N=Cc2nccc[cH]2->[Ru+2])ncc1Br
#20
0.00 ± 0.00
Cc1c(Br)cnc(N=Cc2ccccn2)[cH]1->[Ru+2]
#21
0.00 ± 0.00
Cc1cc(N=Cc2c[cH](->[Ru+2])ccn2)ncc1Br