#1
TOP-1
0.99 ± 0.00
Brc1ccc([N]2=Cc3cccc[n]3->[Ru+2]<-2)nc1
#2
0.00 ± 0.00
Brc1ccc2N=Cc3cccc[n]3->[Ru+2]<-[n]2c1
#3
0.00 ± 0.00
Brc1ccc2[N](=Cc3ccccn3)->[Ru+2]<-[n]2c1
#4
0.00 ± 0.00
Brc1ccc([N]2[Ru+2][CH]2c2ccccn2)nc1
#5
0.00 ± 0.00
Brc1ccc(N=Cc2ccccn2)[n](->[Ru+2])c1
#6
0.00 ± 0.00
Brc1ccc(N=Cc2cccc[n]2->[Ru+2])nc1
#7
0.00 ± 0.00
Brc1ccc([N]2=Cc3nccc[cH]3->[Ru+2]<-2)nc1
#8
0.00 ± 0.00
Brc1ccc(N=C[c]23->[Ru+2]<-[n]2cccc3)nc1
#9
0.00 ± 0.00
Brc1cnc2N=Cc3cccc[n]3->[Ru+2]3<-[cH]1[cH]->32
#10
0.00 ± 0.00
Brc1ccc2N=Cc3ncc[cH]4->[Ru+2](<-[cH]34)<-[n]2c1
#11
0.00 ± 0.00
Brc1cnc(N=Cc2ccccn2)[cH]2->[Ru+2]<-[cH]12
#12
0.00 ± 0.00
Brc1ccc([N](->[Ru+2])=Cc2ccccn2)nc1
#13
0.00 ± 0.00
Brc1ccc2N=Cc3c[cH]4->[Ru+2](<-[cH]4cn3)<-[n]2c1
#14
0.00 ± 0.00
Brc1ccc(N=Cc2c[cH]3->[Ru+2]<-[cH]3cn2)nc1
#15
0.00 ± 0.00
Brc1ccc(N=Cc2ncc[cH]3->[Ru+2]<-[cH]23)nc1
#16
0.00 ± 0.00
Brc1ccc(N=CC2=C[CH]3[Ru+2][CH]3C=N2)nc1
#17
0.00 ± 0.00
Brc1ccc(N=Cc2nc[cH]3->[Ru+]4<-[cH]2[cH]->43)nc1
#18
0.00 ± 0.00
Brc1cnc2N=Cc3cc[cH](->[Ru+2]4<-[cH]1[cH]->42)cn3
#19
0.00 ± 0.00
Brc1cnc2N=Cc3ncc[cH]4->[Ru+2](<-[cH]2c1)<-[cH]34
#20
0.00 ± 0.00
Brc1cnc2N=Cc3c[cH]4->[Ru+2](<-[cH]2c1)<-[cH]4cn3
#21
0.00 ± 0.00
Brc1cnc2N=Cc3nccc[cH]3->[Ru+2]3<-[cH]1[cH]->32
#22
0.00 ± 0.00
Brc1cnc2N=Cc3c[cH](->[Ru+2]4<-[cH]1[cH]->42)ccn3
#23
0.00 ± 0.00
Brc1ccc(N=Cc2cc[cH](->[Ru+2])cn2)nc1
#24
0.00 ± 0.00
Brc1cnc(N=Cc2ccccn2)[cH](->[Ru+2])c1
#25
0.00 ± 0.00
Brc1cnc2N=Cc3ncc[cH]4->[Ru+2](<-[cH]1c2)<-[cH]34
#26
0.00 ± 0.00
Brc1cnc2N=Cc3c[cH]4->[Ru+2](<-[cH]1c2)<-[cH]4cn3
#27
0.00 ± 0.00
Brc1ccc(N=Cc2nccc[cH]2->[Ru+2])nc1
#28
0.00 ± 0.00
Brc1ccc(N=Cc2c[cH](->[Ru+2])ccn2)nc1
#29
0.00 ± 0.00
Brc1cnc(N=Cc2ccccn2)c[cH]1->[Ru+2]