#1
TOP-1
0.12 ± 0.00
C1=CC2SC3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[N]=3C2C=C1
#1
TOP-1
0.12 ± 0.00
C1=CC2SC3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[N]=3C2C=C1
#1
TOP-1
0.12 ± 0.00
C1=CC2SC3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[N]=3C2C=C1
#1
TOP-1
0.12 ± 0.00
C1=CC2SC3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[N]=3C2C=C1
#1
TOP-1
0.12 ± 0.00
C1=CC2SC3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[N]=3C2C=C1
#1
TOP-1
0.12 ± 0.00
C1=CC2SC3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[N]=3C2C=C1
#1
TOP-1
0.12 ± 0.00
C1=CC2SC3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[N]=3C2C=C1
#1
TOP-1
0.12 ± 0.00
C1=CC2SC3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[N]=3C2C=C1
#1
TOP-1
0.12 ± 0.00
C1=CC2SC3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[N]=3C2C=C1
#1
TOP-1
0.35 ± 0.20
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.00 ± 0.00
CC(C)[c]12->[Ru+2]34567(<-[c-]8n(C9=[N]->3C3C=CC=CC3S9)cc[n+]8Cc3ccccc3)<-[cH]([cH]->41)[c]->5(C)[cH...
#2
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2
0.11 ± 0.13
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2
0.00 ± 0.00
CC(C)[c]12->[Ru+2]34567(<-[c-]8n(C9=NC%10C=CC=CC%10[S]->39)cc[n+]8Cc3ccccc3)<-[cH]([cH]->41)[c]->5(C...
#3
0.00 ± 0.00
C1=CC2N=C3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[S]3C2C=C1
#3
0.00 ± 0.00
C1=CC2N=C3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[S]3C2C=C1
#3
0.00 ± 0.00
C1=CC2N=C3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[S]3C2C=C1
#3
0.00 ± 0.00
C1=CC2N=C3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[S]3C2C=C1
#3
0.00 ± 0.00
C1=CC2N=C3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[S]3C2C=C1
#3
0.00 ± 0.00
C1=CC2N=C3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[S]3C2C=C1
#3
0.00 ± 0.00
C1=CC2N=C3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[S]3C2C=C1
#3
0.00 ± 0.00
C1=CC2N=C3n4cc[n+](Cc5ccccc5)[c-]4->[Ru+2]<-[S]3C2C=C1