#1
TOP-1
0.80 ± 0.18
O=C(Cc1ccccc1Nc1c(Cl)cccc1Cl)[O][Ru+]
#2
0.67 ± 0.25
O=C1Cc2ccccc2[NH](->[Ru+][O]1)c1c(Cl)cccc1Cl
#3
0.13 ± 0.21
Clc1cccc(Cl)c1Nc1ccccc1CC1[O][Ru+]<-[O]=1
#4
0.00 ± 0.00
O=C(Cc1ccccc1Nc1c(Cl)cccc1Cl)[O-]->[Ru+2]
#5
0.00 ± 0.00
O=C([O-])Cc1cc[cH]2->[Ru+2]<-[cH]2c1Nc1c(Cl)cccc1Cl
#6
0.00 ± 0.00
O=C([O-])Cc1c(Nc2c(Cl)cccc2Cl)cc[cH]2->[Ru+2]<-[cH]12
#7
0.00 ± 0.00
O=C([O-])CC1=C(Nc2c(Cl)cccc2Cl)[CH]2[Ru+2][CH]2C=C1
#8
0.00 ± 0.00
O=C([O-])CC1=C(Nc2c(Cl)cccc2Cl)C=C[CH]2[Ru+2][CH]12
#9
0.00 ± 0.00
O=C([O-])Cc1c[cH]2->[Ru+]3<-[cH](c1Nc1c(Cl)cccc1Cl)[cH]->32
#10
0.00 ± 0.00
O=C([O-])Cc1c(Nc2c(Cl)cccc2Cl)[cH]2->[Ru+2]34<-[cH]1[cH]->3[cH]->42
#11
0.00 ± 0.00
O=C([O-])Cc1c(Nc2c(Cl)cccc2Cl)c[cH]2->[Ru+]3<-[cH]1[cH]->32
#12
0.00 ± 0.00
O=C([O-])Cc1c[cH]2->[Ru+2]<-[cH]2cc1Nc1c(Cl)cccc1Cl
#13
0.00 ± 0.00
O=C([O-])Cc1ccccc1Nc1c(Cl)c[cH]2->[Ru+2]<-[cH]2c1Cl
#14
0.00 ± 0.00
O=C([O-])Cc1ccccc1Nc1c(Cl)[cH]2->[Ru+]3<-[cH](c1Cl)[cH]->32
#15
0.00 ± 0.00
O=C([O-])CC1=C(Nc2c(Cl)cccc2Cl)[CH]2[CH]3[CH]4[CH]1[Ru+2]243
#16
0.00 ± 0.00
[O-]C(Cc1ccccc1Nc1c(Cl)cccc1Cl)=[O]->[Ru+2]
#17
0.00 ± 0.00
O=C([O-])Cc1c2Nc3c(Cl)c[cH]4->[Ru+2](<-[cH]1ccc2)<-[cH]4c3Cl
#18
0.00 ± 0.00
O=C([O-])Cc1ccc[cH]2->[Ru+2]3<-[cH]4cc(Cl)c(Nc12)c(Cl)[cH]->34
#19
0.00 ± 0.00
O=C([O-])Cc1cc[cH]2->[Ru+2]3<-[cH]4cc(Cl)c(Nc1[cH]->32)c(Cl)c4
#20
0.00 ± 0.00
O=C([O-])Cc1c2Nc3c(Cl)c[cH](->[Ru+2]4<-[cH](cc2)[cH]->41)cc3Cl
#21
0.00 ± 0.00
O=C([O-])Cc1c[cH]2->[Ru+2]3<-[cH]4cc(Cl)c(Nc1cc2)c(Cl)[cH]->34
#22
0.00 ± 0.00
O=C([O-])Cc1c(Nc2c(Cl)cccc2Cl)ccc[cH]1->[Ru+2]
#23
0.00 ± 0.00
O=C([O-])Cc1ccc[cH](->[Ru+2])c1Nc1c(Cl)cccc1Cl
#24
0.00 ± 0.00
O=C([O-])Cc1c[cH]2->[Ru+2]3<-[cH]4cc(Cl)c(Nc1c[cH]->32)c(Cl)c4
#25
0.00 ± 0.00
O=C([O-])Cc1cc[cH]2->[Ru+2]3<-[cH]4ccc(Cl)c(Nc1[cH]->32)c4Cl
#26
0.00 ± 0.00
O=C([O-])Cc1c2Nc3c(Cl)cc[cH](->[Ru+2]4<-[cH](cc2)[cH]->41)c3Cl
#27
0.00 ± 0.00
O=C([O-])Cc1c[cH](->[Ru+2])ccc1Nc1c(Cl)cccc1Cl
#28
0.00 ± 0.00
O=C([O-])Cc1cc[cH]2->[Ru+2]3<-[cH]4cc(Cl)c(Nc1c2)c(Cl)[cH]->34
#29
0.00 ± 0.00
O=C([O-])Cc1ccccc1Nc1c(Cl)c[cH](->[Ru+2])cc1Cl
#30
0.00 ± 0.00
O=C([O-])Cc1c[cH]2->[Ru+2]3<-[cH]4ccc(Cl)c(Nc1c[cH]->32)c4Cl