#1
TOP-1
0.59 ± 0.00
c1ccc([P](->[Ru+2]<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.59 ± 0.00
c1ccc([P](->[Ru+2]<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.59 ± 0.00
c1ccc([P](->[Ru+2]<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.59 ± 0.00
c1ccc([P](->[Ru+2]<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.59 ± 0.00
c1ccc([P](->[Ru+2]<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.59 ± 0.00
c1ccc([P](->[Ru+2]<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.59 ± 0.00
c1ccc([P](->[Ru+2]<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.59 ± 0.00
c1ccc([P](->[Ru+2]<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.59 ± 0.00
c1ccc([P](->[Ru+2]<-[P](c2ccccc2)(c2ccccc2)c2ccccc2)(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.56 ± 0.36
C1=C([O][Ru+]<-[O]=C1c1ccccc1)c1ccccc1
#1
TOP-1
0.54 ± 0.45
C1=C([O][Ru+]2(<-[O]=C1c1ccccc1)<-[n]1ccccc1-c1cccc[n]->21)c1ccccc1
#1
TOP-1
0.50 ± 0.48
C1=C([O][Ru+]2(<-[O]=C1c1ccccc1)(<-[n]1ccccc1-c1cccc[n]->21)<-[P](c1ccccc1)(c1ccccc1)c1ccccc1)c1cccc...
#1
TOP-1
0.39 ± 0.41
C1=C([O][Ru+]2(<-[O]=C1c1ccccc1)(<-[n]1ccccc1-c1cccc[n]->21)(<-[P](c1ccccc1)(c1ccccc1)c1ccccc1)<-[P]...
#2
0.53 ± 0.00
C1/C(=[O]->[Ru+][O]\C=1c1ccccc1)c1ccccc1
#2
0.53 ± 0.00
C1/C(=[O]->[Ru+][O]\C=1c1ccccc1)c1ccccc1
#2
0.53 ± 0.00
C1/C(=[O]->[Ru+][O]\C=1c1ccccc1)c1ccccc1
#2
0.53 ± 0.00
C1/C(=[O]->[Ru+][O]\C=1c1ccccc1)c1ccccc1
#2
0.53 ± 0.00
C1/C(=[O]->[Ru+][O]\C=1c1ccccc1)c1ccccc1
#2
0.53 ± 0.00
C1/C(=[O]->[Ru+][O]\C=1c1ccccc1)c1ccccc1
#2
0.53 ± 0.00
C1/C(=[O]->[Ru+][O]\C=1c1ccccc1)c1ccccc1
#2
0.53 ± 0.00
C1/C(=[O]->[Ru+][O]\C=1c1ccccc1)c1ccccc1
#2
0.53 ± 0.00
C1/C(=[O]->[Ru+][O]\C=1c1ccccc1)c1ccccc1
#2
0.54 ± 0.36
C1\C(=[O]->[Ru+][O]\C=1c1ccccc1)c1ccccc1
#2
0.03 ± 0.05
C1=C([O][Ru+]23(<-[O]=C1c1ccccc1)<-[cH]1ccnc(-c4cccc[n]->24)[cH]->31)c1ccccc1
#2
0.02 ± 0.03
C1=C[CH]2[CH]3C(=C1)P(c1ccccc1)C1=CC=C[CH]4[CH]1[Ru+]24315([O]C(=CC(=[O]->1)c1ccccc1)c1ccccc1)<-[n]1...
#2
0.00 ± 0.00
C1=C[CH]2[CH]3C(=C1)P(c1ccccc1)C1=CC=C[CH]4[CH]1[Ru+]24315([O]C(=CC(=[O]->1)c1ccccc1)c1ccccc1)(<-[n]...
#3
0.02 ± 0.00
[O-]/C(=C\C(=[O]->[Ru+2])c1ccccc1)c1ccccc1
#3
0.02 ± 0.00
[O-]/C(=C\C(=[O]->[Ru+2])c1ccccc1)c1ccccc1
#3
0.02 ± 0.00
[O-]/C(=C\C(=[O]->[Ru+2])c1ccccc1)c1ccccc1
#3
0.02 ± 0.00
[O-]/C(=C\C(=[O]->[Ru+2])c1ccccc1)c1ccccc1