#1
TOP-1
0.10 ± 0.00
C/C(c1ccccn1)=[N]1\NC(N)=[S]->[Ru+2]<-1
#1
TOP-1
0.10 ± 0.00
C/C(c1ccccn1)=[N]1\NC(N)=[S]->[Ru+2]<-1
#1
TOP-1
0.10 ± 0.00
C/C(c1ccccn1)=[N]1\NC(N)=[S]->[Ru+2]<-1
#1
TOP-1
0.10 ± 0.00
C/C(c1ccccn1)=[N]1\NC(N)=[S]->[Ru+2]<-1
#1
TOP-1
0.10 ± 0.00
C/C(c1ccccn1)=[N]1\NC(N)=[S]->[Ru+2]<-1
#1
TOP-1
0.10 ± 0.00
C/C(c1ccccn1)=[N]1\NC(N)=[S]->[Ru+2]<-1
#1
TOP-1
0.10 ± 0.00
C/C(c1ccccn1)=[N]1\NC(N)=[S]->[Ru+2]<-1
#1
TOP-1
0.10 ± 0.00
C/C(c1ccccn1)=[N]1\NC(N)=[S]->[Ru+2]<-1
#1
TOP-1
0.10 ± 0.00
C/C(c1ccccn1)=[N]1\NC(N)=[S]->[Ru+2]<-1
#2
0.06 ± 0.00
CC1c2cccc[n]2->[Ru+2]<-[N]=1NC(N)=S
#2
0.06 ± 0.00
CC1c2cccc[n]2->[Ru+2]<-[N]=1NC(N)=S
#2
0.06 ± 0.00
CC1c2cccc[n]2->[Ru+2]<-[N]=1NC(N)=S
#2
0.06 ± 0.00
CC1c2cccc[n]2->[Ru+2]<-[N]=1NC(N)=S
#2
0.06 ± 0.00
CC1c2cccc[n]2->[Ru+2]<-[N]=1NC(N)=S
#2
0.06 ± 0.00
CC1c2cccc[n]2->[Ru+2]<-[N]=1NC(N)=S
#2
0.06 ± 0.00
CC1c2cccc[n]2->[Ru+2]<-[N]=1NC(N)=S
#2
0.06 ± 0.00
CC1c2cccc[n]2->[Ru+2]<-[N]=1NC(N)=S
#2
0.06 ± 0.00
CC1c2cccc[n]2->[Ru+2]<-[N]=1NC(N)=S
#3
0.03 ± 0.00
C/C1c2cccc[n]2->[Ru+2]<-[N]=1\NC(N)=S
#3
0.03 ± 0.00
C/C1c2cccc[n]2->[Ru+2]<-[N]=1\NC(N)=S
#3
0.03 ± 0.00
C/C1c2cccc[n]2->[Ru+2]<-[N]=1\NC(N)=S
#3
0.03 ± 0.00
C/C1c2cccc[n]2->[Ru+2]<-[N]=1\NC(N)=S
#3
0.03 ± 0.00
C/C1c2cccc[n]2->[Ru+2]<-[N]=1\NC(N)=S
#3
0.03 ± 0.00
C/C1c2cccc[n]2->[Ru+2]<-[N]=1\NC(N)=S
#3
0.03 ± 0.00
C/C1c2cccc[n]2->[Ru+2]<-[N]=1\NC(N)=S
#3
0.03 ± 0.00
C/C1c2cccc[n]2->[Ru+2]<-[N]=1\NC(N)=S
#3
0.03 ± 0.00
C/C1c2cccc[n]2->[Ru+2]<-[N]=1\NC(N)=S
#4
0.02 ± 0.00
C/C(=N\NC(N)=S)c1cccc[n]1->[Ru+2]
#4
0.02 ± 0.00
C/C(=N\NC(N)=S)c1cccc[n]1->[Ru+2]
#4
0.02 ± 0.00
C/C(=N\NC(N)=S)c1cccc[n]1->[Ru+2]