#1
TOP-1
0.87 ± 0.00
C1/C=[N](/Cc2ccccc2)->[Ru+2]<-[N]=1\Cc1ccccc1
#1
TOP-1
0.87 ± 0.00
C1/C=[N](/Cc2ccccc2)->[Ru+2]<-[N]=1\Cc1ccccc1
#1
TOP-1
0.87 ± 0.00
C1/C=[N](/Cc2ccccc2)->[Ru+2]<-[N]=1\Cc1ccccc1
#1
TOP-1
0.87 ± 0.00
C1/C=[N](/Cc2ccccc2)->[Ru+2]<-[N]=1\Cc1ccccc1
#1
TOP-1
0.87 ± 0.00
C1/C=[N](/Cc2ccccc2)->[Ru+2]<-[N]=1\Cc1ccccc1
#1
TOP-1
0.87 ± 0.00
C1/C=[N](/Cc2ccccc2)->[Ru+2]<-[N]=1\Cc1ccccc1
#1
TOP-1
0.87 ± 0.00
C1/C=[N](/Cc2ccccc2)->[Ru+2]<-[N]=1\Cc1ccccc1
#1
TOP-1
0.87 ± 0.00
C1/C=[N](/Cc2ccccc2)->[Ru+2]<-[N]=1\Cc1ccccc1
#1
TOP-1
0.87 ± 0.00
C1/C=[N](/Cc2ccccc2)->[Ru+2]<-[N]=1\Cc1ccccc1
#2
0.56 ± 0.00
C1C=[N](Cc2ccccc2)->[Ru+2]<-[N]=1Cc1ccccc1
#2
0.56 ± 0.00
C1C=[N](Cc2ccccc2)->[Ru+2]<-[N]=1Cc1ccccc1
#2
0.56 ± 0.00
C1C=[N](Cc2ccccc2)->[Ru+2]<-[N]=1Cc1ccccc1
#2
0.56 ± 0.00
C1C=[N](Cc2ccccc2)->[Ru+2]<-[N]=1Cc1ccccc1
#2
0.56 ± 0.00
C1C=[N](Cc2ccccc2)->[Ru+2]<-[N]=1Cc1ccccc1
#2
0.56 ± 0.00
C1C=[N](Cc2ccccc2)->[Ru+2]<-[N]=1Cc1ccccc1
#2
0.56 ± 0.00
C1C=[N](Cc2ccccc2)->[Ru+2]<-[N]=1Cc1ccccc1
#2
0.56 ± 0.00
C1C=[N](Cc2ccccc2)->[Ru+2]<-[N]=1Cc1ccccc1
#2
0.56 ± 0.00
C1C=[N](Cc2ccccc2)->[Ru+2]<-[N]=1Cc1ccccc1
#3
0.23 ± 0.00
C[C]12[C]3(C)[C]4(C)[C]5(C)[C]1(C)[Ru+]2345
#3
0.23 ± 0.00
C[C]12[C]3(C)[C]4(C)[C]5(C)[C]1(C)[Ru+]2345
#3
0.23 ± 0.00
C[C]12[C]3(C)[C]4(C)[C]5(C)[C]1(C)[Ru+]2345
#3
0.23 ± 0.00
C[C]12[C]3(C)[C]4(C)[C]5(C)[C]1(C)[Ru+]2345
#3
0.23 ± 0.00
C[C]12[C]3(C)[C]4(C)[C]5(C)[C]1(C)[Ru+]2345
#3
0.23 ± 0.00
C[C]12[C]3(C)[C]4(C)[C]5(C)[C]1(C)[Ru+]2345
#3
0.23 ± 0.00
C[C]12[C]3(C)[C]4(C)[C]5(C)[C]1(C)[Ru+]2345
#3
0.23 ± 0.00
C[C]12[C]3(C)[C]4(C)[C]5(C)[C]1(C)[Ru+]2345
#3
0.23 ± 0.00
C[C]12[C]3(C)[C]4(C)[C]5(C)[C]1(C)[Ru+]2345
#4
0.13 ± 0.00
C(=N\Cc1ccccc1)/[CH]1[Ru+2][N]1Cc1ccccc1
#4
0.13 ± 0.00
C(=N\Cc1ccccc1)/[CH]1[Ru+2][N]1Cc1ccccc1
#4
0.13 ± 0.00
C(=N\Cc1ccccc1)/[CH]1[Ru+2][N]1Cc1ccccc1