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Complex #892 — Ru(2) [2]

GT: {"N": 3, "P": 1, "O": 1} → Top-1: {"P": 3, "O": 1}
rdmetallics.net (363)Sequential multi-lig (7058)Single-ligand (939)
3
Candidates
{"N": 3, "P": 1, "O": 1}
Ground Truth
{"P": 3, "O": 1}
Top-1 Prediction
0.000
Match Score
⬇ MOL (coordinated) Raw MOL 🔬 3D Viewer Complex detail
⚠ Per-candidate scores unavailable for sequential. Showing 30 candidates from single-ligand scoring. For sequential results only top-1 prediction is stored.
#1 TOP-1 0.99 ± 0.00
[Ru+2]<-[P]12CN3CN(CN(C3)C1)C2
#1 TOP-1 0.99 ± 0.00
[Ru+2]<-[P]12CN3CN(CN(C3)C1)C2
#1 TOP-1 0.99 ± 0.00
[Ru+2]<-[P]12CN3CN(CN(C3)C1)C2
#1 TOP-1 0.99 ± 0.00
[Ru+2]<-[P]12CN3CN(CN(C3)C1)C2
#1 TOP-1 0.99 ± 0.00
[Ru+2]<-[P]12CN3CN(CN(C3)C1)C2
#1 TOP-1 0.99 ± 0.00
[Ru+2]<-[P]12CN3CN(CN(C3)C1)C2
#1 TOP-1 0.99 ± 0.00
[Ru+2]<-[P]12CN3CN(CN(C3)C1)C2
#1 TOP-1 0.99 ± 0.00
[Ru+2]<-[P]12CN3CN(CN(C3)C1)C2
#1 TOP-1 0.99 ± 0.00
[Ru+2]<-[P]12CN3CN(CN(C3)C1)C2
#2 0.69 ± 0.00
FC(F)(F)C1C=C([O][Ru+]<-[O]=1)c1ccc(I)cc1
#2 0.69 ± 0.00
FC(F)(F)C1C=C([O][Ru+]<-[O]=1)c1ccc(I)cc1
#2 0.69 ± 0.00
FC(F)(F)C1C=C([O][Ru+]<-[O]=1)c1ccc(I)cc1
#2 0.69 ± 0.00
FC(F)(F)C1C=C([O][Ru+]<-[O]=1)c1ccc(I)cc1
#2 0.69 ± 0.00
FC(F)(F)C1C=C([O][Ru+]<-[O]=1)c1ccc(I)cc1
#2 0.69 ± 0.00
FC(F)(F)C1C=C([O][Ru+]<-[O]=1)c1ccc(I)cc1
#2 0.69 ± 0.00
FC(F)(F)C1C=C([O][Ru+]<-[O]=1)c1ccc(I)cc1
#2 0.69 ± 0.00
FC(F)(F)C1C=C([O][Ru+]<-[O]=1)c1ccc(I)cc1
#2 0.69 ± 0.00
FC(F)(F)C1C=C([O][Ru+]<-[O]=1)c1ccc(I)cc1
#3 0.62 ± 0.00
O=C(/C=C(\[O][Ru+])c1ccc(I)cc1)C(F)(F)F
#3 0.62 ± 0.00
O=C(/C=C(\[O][Ru+])c1ccc(I)cc1)C(F)(F)F
#3 0.62 ± 0.00
O=C(/C=C(\[O][Ru+])c1ccc(I)cc1)C(F)(F)F
#3 0.62 ± 0.00
O=C(/C=C(\[O][Ru+])c1ccc(I)cc1)C(F)(F)F
#3 0.62 ± 0.00
O=C(/C=C(\[O][Ru+])c1ccc(I)cc1)C(F)(F)F
#3 0.62 ± 0.00
O=C(/C=C(\[O][Ru+])c1ccc(I)cc1)C(F)(F)F
#3 0.62 ± 0.00
O=C(/C=C(\[O][Ru+])c1ccc(I)cc1)C(F)(F)F
#3 0.62 ± 0.00
O=C(/C=C(\[O][Ru+])c1ccc(I)cc1)C(F)(F)F
#3 0.62 ± 0.00
O=C(/C=C(\[O][Ru+])c1ccc(I)cc1)C(F)(F)F
#4 0.60 ± 0.00
FC(F)(F)C1/C=C(\[O][Ru+]<-[O]=1)c1ccc(I)cc1
#4 0.60 ± 0.00
FC(F)(F)C1/C=C(\[O][Ru+]<-[O]=1)c1ccc(I)cc1
#4 0.60 ± 0.00
FC(F)(F)C1/C=C(\[O][Ru+]<-[O]=1)c1ccc(I)cc1