#1
TOP-1
0.46 ± 0.00
c1cc2c3[n](->[Ru+2]<-[n]4cccc(c4-3)C2=Nc2nccs2)c1
#1
TOP-1
0.46 ± 0.00
c1cc2c3[n](->[Ru+2]<-[n]4cccc(c4-3)C2=Nc2nccs2)c1
#1
TOP-1
0.46 ± 0.00
c1cc2c3[n](->[Ru+2]<-[n]4cccc(c4-3)C2=Nc2nccs2)c1
#1
TOP-1
0.46 ± 0.00
c1cc2c3[n](->[Ru+2]<-[n]4cccc(c4-3)C2=Nc2nccs2)c1
#1
TOP-1
0.46 ± 0.00
c1cc2c3[n](->[Ru+2]<-[n]4cccc(c4-3)C2=Nc2nccs2)c1
#1
TOP-1
0.46 ± 0.00
c1cc2c3[n](->[Ru+2]<-[n]4cccc(c4-3)C2=Nc2nccs2)c1
#1
TOP-1
0.46 ± 0.00
c1cc2c3[n](->[Ru+2]<-[n]4cccc(c4-3)C2=Nc2nccs2)c1
#1
TOP-1
0.46 ± 0.00
c1cc2c3[n](->[Ru+2]<-[n]4cccc(c4-3)C2=Nc2nccs2)c1
#1
TOP-1
0.46 ± 0.00
c1cc2c3[n](->[Ru+2]<-[n]4cccc(c4-3)C2=Nc2nccs2)c1
#2
0.31 ± 0.00
c1cc2c3[n](->[Ru+2]4<-[N](=C2c2ccc[n]->4c2-3)c2nccs2)c1
#2
0.31 ± 0.00
c1cc2c3[n](->[Ru+2]4<-[N](=C2c2ccc[n]->4c2-3)c2nccs2)c1
#2
0.31 ± 0.00
c1cc2c3[n](->[Ru+2]4<-[N](=C2c2ccc[n]->4c2-3)c2nccs2)c1
#2
0.31 ± 0.00
c1cc2c3[n](->[Ru+2]4<-[N](=C2c2ccc[n]->4c2-3)c2nccs2)c1
#2
0.31 ± 0.00
c1cc2c3[n](->[Ru+2]4<-[N](=C2c2ccc[n]->4c2-3)c2nccs2)c1
#2
0.31 ± 0.00
c1cc2c3[n](->[Ru+2]4<-[N](=C2c2ccc[n]->4c2-3)c2nccs2)c1
#2
0.31 ± 0.00
c1cc2c3[n](->[Ru+2]4<-[N](=C2c2ccc[n]->4c2-3)c2nccs2)c1
#2
0.31 ± 0.00
c1cc2c3[n](->[Ru+2]4<-[N](=C2c2ccc[n]->4c2-3)c2nccs2)c1
#2
0.31 ± 0.00
c1cc2c3[n](->[Ru+2]4<-[N](=C2c2ccc[n]->4c2-3)c2nccs2)c1
#3
0.17 ± 0.00
C1=C[C]23[C]4(N=C1)[c]15->[Ru+]246<-[C]3(=Nc2nccs2)[c]->61cccn5
#3
0.17 ± 0.00
C1=C[C]23[C]4(N=C1)[c]15->[Ru+]246<-[C]3(=Nc2nccs2)[c]->61cccn5
#3
0.17 ± 0.00
C1=C[C]23[C]4(N=C1)[c]15->[Ru+]246<-[C]3(=Nc2nccs2)[c]->61cccn5
#3
0.17 ± 0.00
C1=C[C]23[C]4(N=C1)[c]15->[Ru+]246<-[C]3(=Nc2nccs2)[c]->61cccn5
#3
0.17 ± 0.00
C1=C[C]23[C]4(N=C1)[c]15->[Ru+]246<-[C]3(=Nc2nccs2)[c]->61cccn5
#3
0.17 ± 0.00
C1=C[C]23[C]4(N=C1)[c]15->[Ru+]246<-[C]3(=Nc2nccs2)[c]->61cccn5
#3
0.17 ± 0.00
C1=C[C]23[C]4(N=C1)[c]15->[Ru+]246<-[C]3(=Nc2nccs2)[c]->61cccn5
#3
0.17 ± 0.00
C1=C[C]23[C]4(N=C1)[c]15->[Ru+]246<-[C]3(=Nc2nccs2)[c]->61cccn5
#3
0.17 ± 0.00
C1=C[C]23[C]4(N=C1)[c]15->[Ru+]246<-[C]3(=Nc2nccs2)[c]->61cccn5
#4
0.14 ± 0.00
c1ccc([P](c2ccccc2)(c2ccccc2)->[Ru+2]2<-[n]3cccc4c3-c3c(ccc[n]->23)C4=Nc2nccs2)cc1
#4
0.14 ± 0.00
c1ccc([P](c2ccccc2)(c2ccccc2)->[Ru+2]2<-[n]3cccc4c3-c3c(ccc[n]->23)C4=Nc2nccs2)cc1
#4
0.14 ± 0.00
c1ccc([P](c2ccccc2)(c2ccccc2)->[Ru+2]2<-[n]3cccc4c3-c3c(ccc[n]->23)C4=Nc2nccs2)cc1