#1
TOP-1
0.97 ± 0.00
c1cc2ccc3ccc[n]4->[Ru+2]<-[n](c1)c2c34
#1
TOP-1
0.97 ± 0.00
c1cc2ccc3ccc[n]4->[Ru+2]<-[n](c1)c2c34
#1
TOP-1
0.97 ± 0.00
c1cc2ccc3ccc[n]4->[Ru+2]<-[n](c1)c2c34
#1
TOP-1
0.97 ± 0.00
c1cc2ccc3ccc[n]4->[Ru+2]<-[n](c1)c2c34
#1
TOP-1
0.97 ± 0.00
c1cc2ccc3ccc[n]4->[Ru+2]<-[n](c1)c2c34
#1
TOP-1
0.97 ± 0.00
c1cc2ccc3ccc[n]4->[Ru+2]<-[n](c1)c2c34
#1
TOP-1
0.97 ± 0.00
c1cc2ccc3ccc[n]4->[Ru+2]<-[n](c1)c2c34
#1
TOP-1
0.97 ± 0.00
c1cc2ccc3ccc[n]4->[Ru+2]<-[n](c1)c2c34
#1
TOP-1
0.97 ± 0.00
c1cc2ccc3ccc[n]4->[Ru+2]<-[n](c1)c2c34
#2
0.58 ± 0.00
CC(=O)OCC1C(OC(C)=O)OC(n2cc[n+](C)[c-]2->[Ru+2]2<-[n]3cccc4ccc5ccc[n]->2c5c43)C(OC(C)=O)C1OC(C)=O
#2
0.58 ± 0.00
CC(=O)OCC1C(OC(C)=O)OC(n2cc[n+](C)[c-]2->[Ru+2]2<-[n]3cccc4ccc5ccc[n]->2c5c43)C(OC(C)=O)C1OC(C)=O
#2
0.58 ± 0.00
CC(=O)OCC1C(OC(C)=O)OC(n2cc[n+](C)[c-]2->[Ru+2]2<-[n]3cccc4ccc5ccc[n]->2c5c43)C(OC(C)=O)C1OC(C)=O
#2
0.58 ± 0.00
CC(=O)OCC1C(OC(C)=O)OC(n2cc[n+](C)[c-]2->[Ru+2]2<-[n]3cccc4ccc5ccc[n]->2c5c43)C(OC(C)=O)C1OC(C)=O
#2
0.58 ± 0.00
CC(=O)OCC1C(OC(C)=O)OC(n2cc[n+](C)[c-]2->[Ru+2]2<-[n]3cccc4ccc5ccc[n]->2c5c43)C(OC(C)=O)C1OC(C)=O
#2
0.58 ± 0.00
CC(=O)OCC1C(OC(C)=O)OC(n2cc[n+](C)[c-]2->[Ru+2]2<-[n]3cccc4ccc5ccc[n]->2c5c43)C(OC(C)=O)C1OC(C)=O
#2
0.58 ± 0.00
CC(=O)OCC1C(OC(C)=O)OC(n2cc[n+](C)[c-]2->[Ru+2]2<-[n]3cccc4ccc5ccc[n]->2c5c43)C(OC(C)=O)C1OC(C)=O
#2
0.58 ± 0.00
CC(=O)OCC1C(OC(C)=O)OC(n2cc[n+](C)[c-]2->[Ru+2]2<-[n]3cccc4ccc5ccc[n]->2c5c43)C(OC(C)=O)C1OC(C)=O
#2
0.58 ± 0.00
CC(=O)OCC1C(OC(C)=O)OC(n2cc[n+](C)[c-]2->[Ru+2]2<-[n]3cccc4ccc5ccc[n]->2c5c43)C(OC(C)=O)C1OC(C)=O
#3
0.01 ± 0.00
[Ru+2]<-[n]1cccc2ccc3cccnc3c21
#3
0.01 ± 0.00
[Ru+2]<-[n]1cccc2ccc3cccnc3c21
#3
0.01 ± 0.00
[Ru+2]<-[n]1cccc2ccc3cccnc3c21
#3
0.01 ± 0.00
[Ru+2]<-[n]1cccc2ccc3cccnc3c21
#3
0.01 ± 0.00
[Ru+2]<-[n]1cccc2ccc3cccnc3c21
#3
0.01 ± 0.00
[Ru+2]<-[n]1cccc2ccc3cccnc3c21
#3
0.01 ± 0.00
[Ru+2]<-[n]1cccc2ccc3cccnc3c21
#3
0.01 ± 0.00
[Ru+2]<-[n]1cccc2ccc3cccnc3c21
#3
0.01 ± 0.00
[Ru+2]<-[n]1cccc2ccc3cccnc3c21
#4
0.00 ± 0.00
C1=Nc2c(ccc3cccnc23)[CH]2[Ru+2][CH]12
#4
0.00 ± 0.00
C1=Nc2c(ccc3cccnc23)[CH]2[Ru+2][CH]12
#4
0.00 ± 0.00
C1=Nc2c(ccc3cccnc23)[CH]2[Ru+2][CH]12