#1
TOP-1
0.55 ± 0.00
c1cc[n]2->[Ru+2]<-[n]3ccccc3-c2c1
#1
TOP-1
0.55 ± 0.00
c1cc[n]2->[Ru+2]<-[n]3ccccc3-c2c1
#1
TOP-1
0.55 ± 0.00
c1cc[n]2->[Ru+2]<-[n]3ccccc3-c2c1
#1
TOP-1
0.55 ± 0.00
c1cc[n]2->[Ru+2]<-[n]3ccccc3-c2c1
#1
TOP-1
0.55 ± 0.00
c1cc[n]2->[Ru+2]<-[n]3ccccc3-c2c1
#1
TOP-1
0.55 ± 0.00
c1cc[n]2->[Ru+2]<-[n]3ccccc3-c2c1
#1
TOP-1
0.55 ± 0.00
c1cc[n]2->[Ru+2]<-[n]3ccccc3-c2c1
#1
TOP-1
0.55 ± 0.00
c1cc[n]2->[Ru+2]<-[n]3ccccc3-c2c1
#1
TOP-1
0.55 ± 0.00
c1cc[n]2->[Ru+2]<-[n]3ccccc3-c2c1
#2
0.07 ± 0.00
S=C(N/N=C/c1ccncc1)N[N]1=Cc2ccc3ccccc3[n]2->[Ru+2]<-1
#2
0.07 ± 0.00
S=C(N/N=C/c1ccncc1)N[N]1=Cc2ccc3ccccc3[n]2->[Ru+2]<-1
#2
0.07 ± 0.00
S=C(N/N=C/c1ccncc1)N[N]1=Cc2ccc3ccccc3[n]2->[Ru+2]<-1
#2
0.07 ± 0.00
S=C(N/N=C/c1ccncc1)N[N]1=Cc2ccc3ccccc3[n]2->[Ru+2]<-1
#2
0.07 ± 0.00
S=C(N/N=C/c1ccncc1)N[N]1=Cc2ccc3ccccc3[n]2->[Ru+2]<-1
#2
0.07 ± 0.00
S=C(N/N=C/c1ccncc1)N[N]1=Cc2ccc3ccccc3[n]2->[Ru+2]<-1
#2
0.07 ± 0.00
S=C(N/N=C/c1ccncc1)N[N]1=Cc2ccc3ccccc3[n]2->[Ru+2]<-1
#2
0.07 ± 0.00
S=C(N/N=C/c1ccncc1)N[N]1=Cc2ccc3ccccc3[n]2->[Ru+2]<-1
#2
0.07 ± 0.00
S=C(N/N=C/c1ccncc1)N[N]1=Cc2ccc3ccccc3[n]2->[Ru+2]<-1
#3
0.02 ± 0.00
C(/c1ccc2ccccc2n1)=[N]1\NC(N/N=C/c2ccncc2)=[S]->[Ru+2]<-1
#3
0.02 ± 0.00
C(/c1ccc2ccccc2n1)=[N]1\NC(N/N=C/c2ccncc2)=[S]->[Ru+2]<-1
#3
0.02 ± 0.00
C(/c1ccc2ccccc2n1)=[N]1\NC(N/N=C/c2ccncc2)=[S]->[Ru+2]<-1
#3
0.02 ± 0.00
C(/c1ccc2ccccc2n1)=[N]1\NC(N/N=C/c2ccncc2)=[S]->[Ru+2]<-1
#3
0.02 ± 0.00
C(/c1ccc2ccccc2n1)=[N]1\NC(N/N=C/c2ccncc2)=[S]->[Ru+2]<-1
#3
0.02 ± 0.00
C(/c1ccc2ccccc2n1)=[N]1\NC(N/N=C/c2ccncc2)=[S]->[Ru+2]<-1
#3
0.02 ± 0.00
C(/c1ccc2ccccc2n1)=[N]1\NC(N/N=C/c2ccncc2)=[S]->[Ru+2]<-1
#3
0.02 ± 0.00
C(/c1ccc2ccccc2n1)=[N]1\NC(N/N=C/c2ccncc2)=[S]->[Ru+2]<-1
#3
0.02 ± 0.00
C(/c1ccc2ccccc2n1)=[N]1\NC(N/N=C/c2ccncc2)=[S]->[Ru+2]<-1
#4
0.00 ± 0.00
S=C1N/N=C/c2ccc3ccccc3[n]2->[Ru+2]<-[N](=C\c2ccncc2)/N1
#4
0.00 ± 0.00
S=C1N/N=C/c2ccc3ccccc3[n]2->[Ru+2]<-[N](=C\c2ccncc2)/N1
#4
0.00 ± 0.00
S=C1N/N=C/c2ccc3ccccc3[n]2->[Ru+2]<-[N](=C\c2ccncc2)/N1