home← all results complex #639

Complex #639 — Ru(2) [Ru1]

GT: {"N": 6} → Top-1: {"N": 10}
rdmetallics.net (363)Sequential multi-lig (7058)Single-ligand (939)
3
Candidates
{"N": 6}
Ground Truth
{"N": 10}
Top-1 Prediction
0.600
Match Score
⬇ MOL (coordinated) Raw MOL 🔬 3D Viewer Complex detail
⚠ Per-candidate scores unavailable for sequential. Showing 30 candidates from single-ligand scoring. For sequential results only top-1 prediction is stored.
#1 TOP-1 0.11 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]1<-[n]2cccc3cc(NC(=O)CCCCC[...
#1 TOP-1 0.11 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]1<-[n]2cccc3cc(NC(=O)CCCCC[...
#1 TOP-1 0.11 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]1<-[n]2cccc3cc(NC(=O)CCCCC[...
#1 TOP-1 0.11 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]1<-[n]2cccc3cc(NC(=O)CCCCC[...
#1 TOP-1 0.11 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]1<-[n]2cccc3cc(NC(=O)CCCCC[...
#1 TOP-1 0.11 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]1<-[n]2cccc3cc(NC(=O)CCCCC[...
#1 TOP-1 0.11 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]1<-[n]2cccc3cc(NC(=O)CCCCC[...
#1 TOP-1 0.11 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]1<-[n]2cccc3cc(NC(=O)CCCCC[...
#1 TOP-1 0.11 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]1<-[n]2cccc3cc(NC(=O)CCCCC[...
#2 0.04 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]
#2 0.04 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]
#2 0.04 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]
#2 0.04 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]
#2 0.04 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]
#2 0.04 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]
#2 0.04 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]
#2 0.04 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]
#2 0.04 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2cccnc2c2c1ccc[n]2->[Ru+2]
#3 0.01 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12
#3 0.01 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12
#3 0.01 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12
#3 0.01 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12
#3 0.01 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12
#3 0.01 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12
#3 0.01 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12
#3 0.01 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12
#3 0.01 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12
#4 0.00 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2c3nc[cH]4->[Ru+2](<-[cH]24)<-[n]2cccc1c32
#4 0.00 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2c3nc[cH]4->[Ru+2](<-[cH]24)<-[n]2cccc1c32
#4 0.00 ± 0.00
O=C(CCCCC[P+](c1ccccc1)(c1ccccc1)c1ccccc1)Nc1cc2c3nc[cH]4->[Ru+2](<-[cH]24)<-[n]2cccc1c32