#1
TOP-1
0.02 ± 0.00
O=C1C(C2CCCCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#1
TOP-1
0.02 ± 0.00
O=C1C(C2CCCCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#1
TOP-1
0.02 ± 0.00
O=C1C(C2CCCCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#1
TOP-1
0.02 ± 0.00
O=C1C(C2CCCCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#1
TOP-1
0.02 ± 0.00
O=C1C(C2CCCCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#1
TOP-1
0.02 ± 0.00
O=C1C(C2CCCCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#1
TOP-1
0.02 ± 0.00
O=C1C(C2CCCCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#1
TOP-1
0.02 ± 0.00
O=C1C(C2CCCCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#1
TOP-1
0.02 ± 0.00
O=C1C(C2CCCCC2)=C2[O-]->[Ru+][O]C2(n2cccn2)c2ccccc21
#2
0.01 ± 0.00
O=C1C(C2CCCCC2)=C([O-])C2([O][Ru+]<-[n]3cccn32)c2ccccc21
#2
0.01 ± 0.00
O=C1C(C2CCCCC2)=C([O-])C2([O][Ru+]<-[n]3cccn32)c2ccccc21
#2
0.01 ± 0.00
O=C1C(C2CCCCC2)=C([O-])C2([O][Ru+]<-[n]3cccn32)c2ccccc21
#2
0.01 ± 0.00
O=C1C(C2CCCCC2)=C([O-])C2([O][Ru+]<-[n]3cccn32)c2ccccc21
#2
0.01 ± 0.00
O=C1C(C2CCCCC2)=C([O-])C2([O][Ru+]<-[n]3cccn32)c2ccccc21
#2
0.01 ± 0.00
O=C1C(C2CCCCC2)=C([O-])C2([O][Ru+]<-[n]3cccn32)c2ccccc21
#2
0.01 ± 0.00
O=C1C(C2CCCCC2)=C([O-])C2([O][Ru+]<-[n]3cccn32)c2ccccc21
#2
0.01 ± 0.00
O=C1C(C2CCCCC2)=C([O-])C2([O][Ru+]<-[n]3cccn32)c2ccccc21
#2
0.01 ± 0.00
O=C1C(C2CCCCC2)=C([O-])C2([O][Ru+]<-[n]3cccn32)c2ccccc21
#3
0.00 ± 0.00
O=C1C(C2CCCCC2)=C2[O][Ru+]<-[O-]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(C2CCCCC2)=C2[O][Ru+]<-[O-]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(C2CCCCC2)=C2[O][Ru+]<-[O-]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(C2CCCCC2)=C2[O][Ru+]<-[O-]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(C2CCCCC2)=C2[O][Ru+]<-[O-]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(C2CCCCC2)=C2[O][Ru+]<-[O-]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(C2CCCCC2)=C2[O][Ru+]<-[O-]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(C2CCCCC2)=C2[O][Ru+]<-[O-]C2(n2cccn2)c2ccccc21
#3
0.00 ± 0.00
O=C1C(C2CCCCC2)=C2[O][Ru+]<-[O-]C2(n2cccn2)c2ccccc21
#4
0.00 ± 0.00
O=C1C(C2CCCCC2)=C([O-])C([O][Ru+])(n2cccn2)c2ccccc21
#4
0.00 ± 0.00
O=C1C(C2CCCCC2)=C([O-])C([O][Ru+])(n2cccn2)c2ccccc21
#4
0.00 ± 0.00
O=C1C(C2CCCCC2)=C([O-])C([O][Ru+])(n2cccn2)c2ccccc21