#1
TOP-1
0.00 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2](<-[cH]12)<-[n]1ccccc1C=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.00 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2](<-[cH]12)<-[n]1ccccc1C=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.00 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2](<-[cH]12)<-[n]1ccccc1C=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.00 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2](<-[cH]12)<-[n]1ccccc1C=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.00 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2](<-[cH]12)<-[n]1ccccc1C=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.00 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2](<-[cH]12)<-[n]1ccccc1C=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.00 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2](<-[cH]12)<-[n]1ccccc1C=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.00 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2](<-[cH]12)<-[n]1ccccc1C=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1
#1
TOP-1
0.00 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2](<-[cH]12)<-[n]1ccccc1C=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1
#2
0.00 ± 0.00
C(=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1)c1ncc[cH]2->[Ru+2]<-[cH]12
#2
0.00 ± 0.00
C(=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1)c1ncc[cH]2->[Ru+2]<-[cH]12
#2
0.00 ± 0.00
C(=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1)c1ncc[cH]2->[Ru+2]<-[cH]12
#2
0.00 ± 0.00
C(=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1)c1ncc[cH]2->[Ru+2]<-[cH]12
#2
0.00 ± 0.00
C(=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1)c1ncc[cH]2->[Ru+2]<-[cH]12
#2
0.00 ± 0.00
C(=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1)c1ncc[cH]2->[Ru+2]<-[cH]12
#2
0.00 ± 0.00
C(=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1)c1ncc[cH]2->[Ru+2]<-[cH]12
#2
0.00 ± 0.00
C(=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1)c1ncc[cH]2->[Ru+2]<-[cH]12
#2
0.00 ± 0.00
C(=Nc1ccc(N(c2ccccc2)c2ccccc2)cc1)c1ncc[cH]2->[Ru+2]<-[cH]12
#3
0.00 ± 0.00
C1=NC(C=Nc2ccc(N(c3ccccc3)c3ccccc3)cc2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(C=Nc2ccc(N(c3ccccc3)c3ccccc3)cc2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(C=Nc2ccc(N(c3ccccc3)c3ccccc3)cc2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(C=Nc2ccc(N(c3ccccc3)c3ccccc3)cc2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(C=Nc2ccc(N(c3ccccc3)c3ccccc3)cc2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(C=Nc2ccc(N(c3ccccc3)c3ccccc3)cc2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(C=Nc2ccc(N(c3ccccc3)c3ccccc3)cc2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(C=Nc2ccc(N(c3ccccc3)c3ccccc3)cc2)=C[CH]2[Ru+2][CH]12
#3
0.00 ± 0.00
C1=NC(C=Nc2ccc(N(c3ccccc3)c3ccccc3)cc2)=C[CH]2[Ru+2][CH]12
#4
0.00 ± 0.00
C(=Nc1ccc(N(c2ccccc2)c2cc[cH]3->[Ru+]4<-[cH]2[cH]->43)cc1)c1ccccn1
#4
0.00 ± 0.00
C(=Nc1ccc(N(c2ccccc2)c2cc[cH]3->[Ru+]4<-[cH]2[cH]->43)cc1)c1ccccn1
#4
0.00 ± 0.00
C(=Nc1ccc(N(c2ccccc2)c2cc[cH]3->[Ru+]4<-[cH]2[cH]->43)cc1)c1ccccn1