#1
TOP-1
0.00 ± 0.00
C1=C[CH]2[Ru+2][CH]2c2c1n(-c1ccc(N=Cc3ccccn3)cc1)c1ccccc21
#1
TOP-1
0.00 ± 0.00
C1=C[CH]2[Ru+2][CH]2c2c1n(-c1ccc(N=Cc3ccccn3)cc1)c1ccccc21
#1
TOP-1
0.00 ± 0.00
C1=C[CH]2[Ru+2][CH]2c2c1n(-c1ccc(N=Cc3ccccn3)cc1)c1ccccc21
#1
TOP-1
0.00 ± 0.00
C1=C[CH]2[Ru+2][CH]2c2c1n(-c1ccc(N=Cc3ccccn3)cc1)c1ccccc21
#1
TOP-1
0.00 ± 0.00
C1=C[CH]2[Ru+2][CH]2c2c1n(-c1ccc(N=Cc3ccccn3)cc1)c1ccccc21
#1
TOP-1
0.00 ± 0.00
C1=C[CH]2[Ru+2][CH]2c2c1n(-c1ccc(N=Cc3ccccn3)cc1)c1ccccc21
#1
TOP-1
0.00 ± 0.00
C1=C[CH]2[Ru+2][CH]2c2c1n(-c1ccc(N=Cc3ccccn3)cc1)c1ccccc21
#1
TOP-1
0.00 ± 0.00
C1=C[CH]2[Ru+2][CH]2c2c1n(-c1ccc(N=Cc3ccccn3)cc1)c1ccccc21
#1
TOP-1
0.00 ± 0.00
C1=C[CH]2[Ru+2][CH]2c2c1n(-c1ccc(N=Cc3ccccn3)cc1)c1ccccc21
#2
0.00 ± 0.00
C(=Nc1ccc(-n2c3ccccc3c3ccccc32)cc1)[c]12->[Ru+2]<-[n]1cccc2
#2
0.00 ± 0.00
C(=Nc1ccc(-n2c3ccccc3c3ccccc32)cc1)[c]12->[Ru+2]<-[n]1cccc2
#2
0.00 ± 0.00
C(=Nc1ccc(-n2c3ccccc3c3ccccc32)cc1)[c]12->[Ru+2]<-[n]1cccc2
#2
0.00 ± 0.00
C(=Nc1ccc(-n2c3ccccc3c3ccccc32)cc1)[c]12->[Ru+2]<-[n]1cccc2
#2
0.00 ± 0.00
C(=Nc1ccc(-n2c3ccccc3c3ccccc32)cc1)[c]12->[Ru+2]<-[n]1cccc2
#2
0.00 ± 0.00
C(=Nc1ccc(-n2c3ccccc3c3ccccc32)cc1)[c]12->[Ru+2]<-[n]1cccc2
#2
0.00 ± 0.00
C(=Nc1ccc(-n2c3ccccc3c3ccccc32)cc1)[c]12->[Ru+2]<-[n]1cccc2
#2
0.00 ± 0.00
C(=Nc1ccc(-n2c3ccccc3c3ccccc32)cc1)[c]12->[Ru+2]<-[n]1cccc2
#2
0.00 ± 0.00
C(=Nc1ccc(-n2c3ccccc3c3ccccc32)cc1)[c]12->[Ru+2]<-[n]1cccc2
#3
0.00 ± 0.00
C(=Nc1ccc(-n2c3c(c4ccccc42)[CH]2[CH]4[CH]5[CH]3[Ru+2]245)cc1)c1ccccn1
#3
0.00 ± 0.00
C(=Nc1ccc(-n2c3c(c4ccccc42)[CH]2[CH]4[CH]5[CH]3[Ru+2]245)cc1)c1ccccn1
#3
0.00 ± 0.00
C(=Nc1ccc(-n2c3c(c4ccccc42)[CH]2[CH]4[CH]5[CH]3[Ru+2]245)cc1)c1ccccn1
#3
0.00 ± 0.00
C(=Nc1ccc(-n2c3c(c4ccccc42)[CH]2[CH]4[CH]5[CH]3[Ru+2]245)cc1)c1ccccn1
#3
0.00 ± 0.00
C(=Nc1ccc(-n2c3c(c4ccccc42)[CH]2[CH]4[CH]5[CH]3[Ru+2]245)cc1)c1ccccn1
#3
0.00 ± 0.00
C(=Nc1ccc(-n2c3c(c4ccccc42)[CH]2[CH]4[CH]5[CH]3[Ru+2]245)cc1)c1ccccn1
#3
0.00 ± 0.00
C(=Nc1ccc(-n2c3c(c4ccccc42)[CH]2[CH]4[CH]5[CH]3[Ru+2]245)cc1)c1ccccn1
#3
0.00 ± 0.00
C(=Nc1ccc(-n2c3c(c4ccccc42)[CH]2[CH]4[CH]5[CH]3[Ru+2]245)cc1)c1ccccn1
#3
0.00 ± 0.00
C(=Nc1ccc(-n2c3c(c4ccccc42)[CH]2[CH]4[CH]5[CH]3[Ru+2]245)cc1)c1ccccn1
#4
0.00 ± 0.00
C1=NC(C=Nc2ccc(-n3c4ccccc4c4ccccc43)cc2)=C[CH]2[Ru+2][CH]12
#4
0.00 ± 0.00
C1=NC(C=Nc2ccc(-n3c4ccccc4c4ccccc43)cc2)=C[CH]2[Ru+2][CH]12
#4
0.00 ± 0.00
C1=NC(C=Nc2ccc(-n3c4ccccc4c4ccccc43)cc2)=C[CH]2[Ru+2][CH]12