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Complex #439 — Ru(2) [8d]

GT: {"N": 5} → Top-1: {"O": 2, "N": 2}
rdmetallics.net (363)Sequential multi-lig (7058)Single-ligand (939)
2
Candidates
{"N": 5}
Ground Truth
{"O": 2, "N": 2}
Top-1 Prediction
0.286
Match Score
⚠ Per-candidate scores unavailable for sequential. Showing 30 candidates from single-ligand scoring. For sequential results only top-1 prediction is stored.
#1 TOP-1 0.56 ± 0.00
CC(NCc1ccc(C)cc1)=[O]->[Ru+2]
#1 TOP-1 0.56 ± 0.00
CC(NCc1ccc(C)cc1)=[O]->[Ru+2]
#1 TOP-1 0.56 ± 0.00
CC(NCc1ccc(C)cc1)=[O]->[Ru+2]
#1 TOP-1 0.56 ± 0.00
CC(NCc1ccc(C)cc1)=[O]->[Ru+2]
#1 TOP-1 0.56 ± 0.00
CC(NCc1ccc(C)cc1)=[O]->[Ru+2]
#1 TOP-1 0.56 ± 0.00
CC(NCc1ccc(C)cc1)=[O]->[Ru+2]
#1 TOP-1 0.56 ± 0.00
CC(NCc1ccc(C)cc1)=[O]->[Ru+2]
#1 TOP-1 0.56 ± 0.00
CC(NCc1ccc(C)cc1)=[O]->[Ru+2]
#1 TOP-1 0.56 ± 0.00
CC(NCc1ccc(C)cc1)=[O]->[Ru+2]
#2 0.01 ± 0.00
CC(=O)NCc1ccc(C)[cH]2->[Ru+2]<-[cH]12
#2 0.01 ± 0.00
CC(=O)NCc1ccc(C)[cH]2->[Ru+2]<-[cH]12
#2 0.01 ± 0.00
CC(=O)NCc1ccc(C)[cH]2->[Ru+2]<-[cH]12
#2 0.01 ± 0.00
CC(=O)NCc1ccc(C)[cH]2->[Ru+2]<-[cH]12
#2 0.01 ± 0.00
CC(=O)NCc1ccc(C)[cH]2->[Ru+2]<-[cH]12
#2 0.01 ± 0.00
CC(=O)NCc1ccc(C)[cH]2->[Ru+2]<-[cH]12
#2 0.01 ± 0.00
CC(=O)NCc1ccc(C)[cH]2->[Ru+2]<-[cH]12
#2 0.01 ± 0.00
CC(=O)NCc1ccc(C)[cH]2->[Ru+2]<-[cH]12
#2 0.01 ± 0.00
CC(=O)NCc1ccc(C)[cH]2->[Ru+2]<-[cH]12
#3 0.00 ± 0.00
O=C(CCCCCCC(=O)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12)NO
#3 0.00 ± 0.00
O=C(CCCCCCC(=O)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12)NO
#3 0.00 ± 0.00
O=C(CCCCCCC(=O)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12)NO
#3 0.00 ± 0.00
O=C(CCCCCCC(=O)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12)NO
#3 0.00 ± 0.00
O=C(CCCCCCC(=O)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12)NO
#3 0.00 ± 0.00
O=C(CCCCCCC(=O)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12)NO
#3 0.00 ± 0.00
O=C(CCCCCCC(=O)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12)NO
#3 0.00 ± 0.00
O=C(CCCCCCC(=O)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12)NO
#3 0.00 ± 0.00
O=C(CCCCCCC(=O)Nc1cc2ccc[n](->[Ru+2])c2c2ncccc12)NO
#4 0.00 ± 0.00
O=C1CCCCCCC(NO)=[O]->[Ru+2]<-[n]2cccc3cc(N1)c1cccnc1c32
#4 0.00 ± 0.00
O=C1CCCCCCC(NO)=[O]->[Ru+2]<-[n]2cccc3cc(N1)c1cccnc1c32
#4 0.00 ± 0.00
O=C1CCCCCCC(NO)=[O]->[Ru+2]<-[n]2cccc3cc(N1)c1cccnc1c32