home← all results complex #429

Complex #429 — Ru(2) [[Ru(C6Me6)L3Cl] (3)]

GT: {"N": 3, "O": 1} → Top-1: {"O": 1, "N": 1}
rdmetallics.net (363)Sequential multi-lig (7058)Single-ligand (939)
2
Candidates
{"N": 3, "O": 1}
Ground Truth
{"O": 1, "N": 1}
Top-1 Prediction
0.000
Match Score
⬇ MOL (coordinated) Raw MOL 🔬 3D Viewer Complex detail
⚠ Per-candidate scores unavailable for sequential. Showing 30 candidates from single-ligand scoring. For sequential results only top-1 prediction is stored.
#1 TOP-1 0.88 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.88 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.88 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.88 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.88 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.88 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.88 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.88 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.88 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#2 0.56 ± 0.00
Cc1c(C)[c]2(C)->[Ru+]3<-[c](C)(c1C)[c]->32C
#2 0.56 ± 0.00
Cc1c(C)[c]2(C)->[Ru+]3<-[c](C)(c1C)[c]->32C
#2 0.56 ± 0.00
Cc1c(C)[c]2(C)->[Ru+]3<-[c](C)(c1C)[c]->32C
#2 0.56 ± 0.00
Cc1c(C)[c]2(C)->[Ru+]3<-[c](C)(c1C)[c]->32C
#2 0.56 ± 0.00
Cc1c(C)[c]2(C)->[Ru+]3<-[c](C)(c1C)[c]->32C
#2 0.56 ± 0.00
Cc1c(C)[c]2(C)->[Ru+]3<-[c](C)(c1C)[c]->32C
#2 0.56 ± 0.00
Cc1c(C)[c]2(C)->[Ru+]3<-[c](C)(c1C)[c]->32C
#2 0.56 ± 0.00
Cc1c(C)[c]2(C)->[Ru+]3<-[c](C)(c1C)[c]->32C
#2 0.56 ± 0.00
Cc1c(C)[c]2(C)->[Ru+]3<-[c](C)(c1C)[c]->32C
#3 0.01 ± 0.00
O=c1c2ccccc2nc2n1-c1ccccc1C2=N[O][Ru+]
#3 0.01 ± 0.00
O=c1c2ccccc2nc2n1-c1ccccc1C2=N[O][Ru+]
#3 0.01 ± 0.00
O=c1c2ccccc2nc2n1-c1ccccc1C2=N[O][Ru+]
#3 0.01 ± 0.00
O=c1c2ccccc2nc2n1-c1ccccc1C2=N[O][Ru+]
#3 0.01 ± 0.00
O=c1c2ccccc2nc2n1-c1ccccc1C2=N[O][Ru+]
#3 0.01 ± 0.00
O=c1c2ccccc2nc2n1-c1ccccc1C2=N[O][Ru+]
#3 0.01 ± 0.00
O=c1c2ccccc2nc2n1-c1ccccc1C2=N[O][Ru+]
#3 0.01 ± 0.00
O=c1c2ccccc2nc2n1-c1ccccc1C2=N[O][Ru+]
#3 0.01 ± 0.00
O=c1c2ccccc2nc2n1-c1ccccc1C2=N[O][Ru+]
#4 0.00 ± 0.00
[O-]N=C1c2ccccc2-n2c1[n]1->[Ru+2]<-[O]=c2c2ccccc21
#4 0.00 ± 0.00
[O-]N=C1c2ccccc2-n2c1[n]1->[Ru+2]<-[O]=c2c2ccccc21
#4 0.00 ± 0.00
[O-]N=C1c2ccccc2-n2c1[n]1->[Ru+2]<-[O]=c2c2ccccc21