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Complex #428 — Ru(2) [[Ru(cym)L3Cl] ]

GT: {"N": 3, "O": 1} → Top-1: C:6(eta)
rdmetallics.net (363)Sequential multi-lig (7058)Single-ligand (939)
2
Candidates
{"N": 3, "O": 1}
Ground Truth
C:6(eta)
Top-1 Prediction
0.000
Match Score
⬇ MOL (coordinated) Raw MOL 🔬 3D Viewer Complex detail
⚠ Per-candidate scores unavailable for sequential. Showing 30 candidates from single-ligand scoring. For sequential results only top-1 prediction is stored.
#1 TOP-1 0.89 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.89 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.89 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.89 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.89 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.89 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.89 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.89 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#1 TOP-1 0.89 ± 0.00
O=c1c2ccccc2[n]2->[Ru+2]<-[N]([O-])=C3c4ccccc4-n1c23
#2 0.00 ± 0.00
O=c1c2ccccc2nc2n1C1=C(C2=N[O-])[CH]2[Ru+2][CH]2C=C1
#2 0.00 ± 0.00
O=c1c2ccccc2nc2n1C1=C(C2=N[O-])[CH]2[Ru+2][CH]2C=C1
#2 0.00 ± 0.00
O=c1c2ccccc2nc2n1C1=C(C2=N[O-])[CH]2[Ru+2][CH]2C=C1
#2 0.00 ± 0.00
O=c1c2ccccc2nc2n1C1=C(C2=N[O-])[CH]2[Ru+2][CH]2C=C1
#2 0.00 ± 0.00
O=c1c2ccccc2nc2n1C1=C(C2=N[O-])[CH]2[Ru+2][CH]2C=C1
#2 0.00 ± 0.00
O=c1c2ccccc2nc2n1C1=C(C2=N[O-])[CH]2[Ru+2][CH]2C=C1
#2 0.00 ± 0.00
O=c1c2ccccc2nc2n1C1=C(C2=N[O-])[CH]2[Ru+2][CH]2C=C1
#2 0.00 ± 0.00
O=c1c2ccccc2nc2n1C1=C(C2=N[O-])[CH]2[Ru+2][CH]2C=C1
#2 0.00 ± 0.00
O=c1c2ccccc2nc2n1C1=C(C2=N[O-])[CH]2[Ru+2][CH]2C=C1
#3 0.00 ± 0.00
O=c1c2ccccc2nc2n1-c1c(cc[cH]3->[Ru+2]<-[cH]13)C2=N[O-]
#3 0.00 ± 0.00
O=c1c2ccccc2nc2n1-c1c(cc[cH]3->[Ru+2]<-[cH]13)C2=N[O-]
#3 0.00 ± 0.00
O=c1c2ccccc2nc2n1-c1c(cc[cH]3->[Ru+2]<-[cH]13)C2=N[O-]
#3 0.00 ± 0.00
O=c1c2ccccc2nc2n1-c1c(cc[cH]3->[Ru+2]<-[cH]13)C2=N[O-]
#3 0.00 ± 0.00
O=c1c2ccccc2nc2n1-c1c(cc[cH]3->[Ru+2]<-[cH]13)C2=N[O-]
#3 0.00 ± 0.00
O=c1c2ccccc2nc2n1-c1c(cc[cH]3->[Ru+2]<-[cH]13)C2=N[O-]
#3 0.00 ± 0.00
O=c1c2ccccc2nc2n1-c1c(cc[cH]3->[Ru+2]<-[cH]13)C2=N[O-]
#3 0.00 ± 0.00
O=c1c2ccccc2nc2n1-c1c(cc[cH]3->[Ru+2]<-[cH]13)C2=N[O-]
#3 0.00 ± 0.00
O=c1c2ccccc2nc2n1-c1c(cc[cH]3->[Ru+2]<-[cH]13)C2=N[O-]
#4 0.00 ± 0.00
O=c1c2ccccc2nc2n1-c1c([cH]3->[Ru+2]45<-[cH]1[cH]->4[cH]->53)C2=N[O-]
#4 0.00 ± 0.00
O=c1c2ccccc2nc2n1-c1c([cH]3->[Ru+2]45<-[cH]1[cH]->4[cH]->53)C2=N[O-]
#4 0.00 ± 0.00
O=c1c2ccccc2nc2n1-c1c([cH]3->[Ru+2]45<-[cH]1[cH]->4[cH]->53)C2=N[O-]