#1
TOP-1
0.04 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.04 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.04 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.04 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.04 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.04 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.04 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.04 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.04 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.35 ± 0.20
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.11 ± 0.25
CC(C)[c]12->[Ru+]34567([O]c8ccc([N+](=O)O)cc8-c8[nH]c9c%10cccnc%10c%10ncccc%10c9[n]->38)<-[cH]([cH]-...
#2
0.00 ± 0.00
O=[N+](O)c1ccc2[O][Ru+]<-[n]3cccc4c5[nH]c(-c2c1)nc5c1cccnc1c43
#2
0.00 ± 0.00
O=[N+](O)c1ccc2[O][Ru+]<-[n]3cccc4c5[nH]c(-c2c1)nc5c1cccnc1c43
#2
0.00 ± 0.00
O=[N+](O)c1ccc2[O][Ru+]<-[n]3cccc4c5[nH]c(-c2c1)nc5c1cccnc1c43
#2
0.00 ± 0.00
O=[N+](O)c1ccc2[O][Ru+]<-[n]3cccc4c5[nH]c(-c2c1)nc5c1cccnc1c43
#2
0.00 ± 0.00
O=[N+](O)c1ccc2[O][Ru+]<-[n]3cccc4c5[nH]c(-c2c1)nc5c1cccnc1c43
#2
0.00 ± 0.00
O=[N+](O)c1ccc2[O][Ru+]<-[n]3cccc4c5[nH]c(-c2c1)nc5c1cccnc1c43
#2
0.00 ± 0.00
O=[N+](O)c1ccc2[O][Ru+]<-[n]3cccc4c5[nH]c(-c2c1)nc5c1cccnc1c43
#2
0.00 ± 0.00
O=[N+](O)c1ccc2[O][Ru+]<-[n]3cccc4c5[nH]c(-c2c1)nc5c1cccnc1c43
#2
0.00 ± 0.00
O=[N+](O)c1ccc2[O][Ru+]<-[n]3cccc4c5[nH]c(-c2c1)nc5c1cccnc1c43
#2
0.11 ± 0.13
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2
0.02 ± 0.04
CC(C)[c]12->[Ru+]34567([O]c8ccc([N+](=O)O)cc8-c8nc9c%10cccnc%10c%10c(ccc[n]->3%10)c9[nH]8)<-[cH]([cH...
#3
0.00 ± 0.00
O=[N+](O)c1ccc([O-])c(-c2[nH]c3c4cccnc4c4ncccc4c3[n]2->[Ru+2])c1
#3
0.00 ± 0.00
O=[N+](O)c1ccc([O-])c(-c2[nH]c3c4cccnc4c4ncccc4c3[n]2->[Ru+2])c1
#3
0.00 ± 0.00
O=[N+](O)c1ccc([O-])c(-c2[nH]c3c4cccnc4c4ncccc4c3[n]2->[Ru+2])c1
#3
0.00 ± 0.00
O=[N+](O)c1ccc([O-])c(-c2[nH]c3c4cccnc4c4ncccc4c3[n]2->[Ru+2])c1
#3
0.00 ± 0.00
O=[N+](O)c1ccc([O-])c(-c2[nH]c3c4cccnc4c4ncccc4c3[n]2->[Ru+2])c1
#3
0.00 ± 0.00
O=[N+](O)c1ccc([O-])c(-c2[nH]c3c4cccnc4c4ncccc4c3[n]2->[Ru+2])c1
#3
0.00 ± 0.00
O=[N+](O)c1ccc([O-])c(-c2[nH]c3c4cccnc4c4ncccc4c3[n]2->[Ru+2])c1
#3
0.00 ± 0.00
O=[N+](O)c1ccc([O-])c(-c2[nH]c3c4cccnc4c4ncccc4c3[n]2->[Ru+2])c1