#1
TOP-1
1.00 ± 0.00
Cc1ccc([N]2=CC=[N](->[Ru+2]<-2)c2ccc(C)cc2)cc1
#1
TOP-1
1.00 ± 0.00
Cc1ccc([N]2=CC=[N](->[Ru+2]<-2)c2ccc(C)cc2)cc1
#1
TOP-1
1.00 ± 0.00
Cc1ccc([N]2=CC=[N](->[Ru+2]<-2)c2ccc(C)cc2)cc1
#1
TOP-1
1.00 ± 0.00
Cc1ccc([N]2=CC=[N](->[Ru+2]<-2)c2ccc(C)cc2)cc1
#1
TOP-1
1.00 ± 0.00
Cc1ccc([N]2=CC=[N](->[Ru+2]<-2)c2ccc(C)cc2)cc1
#1
TOP-1
1.00 ± 0.00
Cc1ccc([N]2=CC=[N](->[Ru+2]<-2)c2ccc(C)cc2)cc1
#1
TOP-1
1.00 ± 0.00
Cc1ccc([N]2=CC=[N](->[Ru+2]<-2)c2ccc(C)cc2)cc1
#1
TOP-1
1.00 ± 0.00
Cc1ccc([N]2=CC=[N](->[Ru+2]<-2)c2ccc(C)cc2)cc1
#1
TOP-1
1.00 ± 0.00
Cc1ccc([N]2=CC=[N](->[Ru+2]<-2)c2ccc(C)cc2)cc1
#1
TOP-1
0.35 ± 0.20
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.39 ± 0.46
Cc1ccc([N]2[CH]3[CH]4[N](c5ccc(C)cc5)[Ru+2]34256789<-[cH]2[cH]->5[c]->6(C(C)C)[cH]->7[cH]->8[c]->92C...
#2
0.25 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#2
0.25 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#2
0.25 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#2
0.25 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#2
0.25 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#2
0.25 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#2
0.25 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#2
0.25 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#2
0.25 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#2
0.11 ± 0.13
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2
0.26 ± 0.39
Cc1ccc([N]2=CC=[N](c3ccc(C)cc3)->[Ru+2]<-234567<-[cH]2[cH]->3[c]->4(C(C)C)[cH]->5[cH]->6[c]->72C)cc1
#3
0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#3
0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#3
0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#3
0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#3
0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#3
0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#3
0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#3
0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12