2
Candidates
{"N": 2}
Ground Truth
C:6(eta)
Top-1 Prediction
0.000
Match Score
⚠ Per-candidate scores unavailable for sequential. Showing 30 candidates from single-ligand scoring.
For sequential results only top-1 prediction is stored.
#1
TOP-1
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.09 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#1
TOP-1
0.35 ± 0.20
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1
TOP-1
0.00 ± 0.00
CC(C)[c]12->[Ru+2]345678(<-[cH]9[c-]c(-c%10[nH]c%11ccccc%11[n]->3%10)cc[cH]->49)<-[cH]([cH]->51)[c]-...
#2
0.00 ± 0.00
[c-]1c2-c3[nH]c4ccccc4[n]3->[Ru+2]3<-[cH]1[cH]->3cc2
#2
0.00 ± 0.00
[c-]1c2-c3[nH]c4ccccc4[n]3->[Ru+2]3<-[cH]1[cH]->3cc2
#2
0.00 ± 0.00
[c-]1c2-c3[nH]c4ccccc4[n]3->[Ru+2]3<-[cH]1[cH]->3cc2
#2
0.00 ± 0.00
[c-]1c2-c3[nH]c4ccccc4[n]3->[Ru+2]3<-[cH]1[cH]->3cc2
#2
0.00 ± 0.00
[c-]1c2-c3[nH]c4ccccc4[n]3->[Ru+2]3<-[cH]1[cH]->3cc2
#2
0.00 ± 0.00
[c-]1c2-c3[nH]c4ccccc4[n]3->[Ru+2]3<-[cH]1[cH]->3cc2
#2
0.00 ± 0.00
[c-]1c2-c3[nH]c4ccccc4[n]3->[Ru+2]3<-[cH]1[cH]->3cc2
#2
0.00 ± 0.00
[c-]1c2-c3[nH]c4ccccc4[n]3->[Ru+2]3<-[cH]1[cH]->3cc2
#2
0.00 ± 0.00
[c-]1c2-c3[nH]c4ccccc4[n]3->[Ru+2]3<-[cH]1[cH]->3cc2
#2
0.11 ± 0.13
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2
0.00 ± 0.00
CC(C)[c]12->[Ru+2]345678(<-[cH]9cc[c-]c(-c%10[nH]c%11ccccc%11[n]->3%10)[cH]->49)<-[cH]([cH]->51)[c]-...
#3
0.00 ± 0.00
[C-]1=C2C=C[CH]3[CH]1[Ru+2]31[CH]3C=Cc4[nH]c2nc4[CH]31
#3
0.00 ± 0.00
[C-]1=C2C=C[CH]3[CH]1[Ru+2]31[CH]3C=Cc4[nH]c2nc4[CH]31
#3
0.00 ± 0.00
[C-]1=C2C=C[CH]3[CH]1[Ru+2]31[CH]3C=Cc4[nH]c2nc4[CH]31
#3
0.00 ± 0.00
[C-]1=C2C=C[CH]3[CH]1[Ru+2]31[CH]3C=Cc4[nH]c2nc4[CH]31
#3
0.00 ± 0.00
[C-]1=C2C=C[CH]3[CH]1[Ru+2]31[CH]3C=Cc4[nH]c2nc4[CH]31
#3
0.00 ± 0.00
[C-]1=C2C=C[CH]3[CH]1[Ru+2]31[CH]3C=Cc4[nH]c2nc4[CH]31
#3
0.00 ± 0.00
[C-]1=C2C=C[CH]3[CH]1[Ru+2]31[CH]3C=Cc4[nH]c2nc4[CH]31
#3
0.00 ± 0.00
[C-]1=C2C=C[CH]3[CH]1[Ru+2]31[CH]3C=Cc4[nH]c2nc4[CH]31