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Complex #172 — Ru(2) [4c]

GT: {"N": 3} → Top-1: {"N": 4}
rdmetallics.net (363)Sequential multi-lig (7058)Single-ligand (939)
2
Candidates
{"N": 3}
Ground Truth
{"N": 4}
Top-1 Prediction
0.000
Match Score
⬇ MOL (coordinated) Raw MOL 🔬 3D Viewer Complex detail
⚠ Per-candidate scores unavailable for sequential. Showing 30 candidates from single-ligand scoring. For sequential results only top-1 prediction is stored.
#1 TOP-1 0.29 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1 TOP-1 0.29 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1 TOP-1 0.29 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1 TOP-1 0.29 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1 TOP-1 0.29 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1 TOP-1 0.29 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1 TOP-1 0.29 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1 TOP-1 0.29 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1 TOP-1 0.29 ± 0.00
CC(C)[c]12->[Ru+2]3456<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62
#1 TOP-1 0.99 ± 0.00
Brc1cnc([N]2=Cc3cccc[n]3->[Ru+2]<-2)c(Br)c1
#1 TOP-1 0.08 ± 0.16
CC(C)[c]12->[Ru+2]34567(<-[cH]([cH]->31)[c]->4(C)[cH]->5[cH]->62)<-[N](=Cc1cccc[n]->71)c1ncc(Br)cc1B...
#1 TOP-1 0.99 ± 0.00
Brc1cnc([N]2=Cc3cccc[n]3->[Ru+2]<-2)c(Br)c1
#2 0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2 0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2 0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2 0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2 0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2 0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2 0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2 0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2 0.03 ± 0.00
Cc1ccc(C(C)C)[cH]2->[Ru+2]<-[cH]12
#2 0.00 ± 0.00
Brc1cc(Br)c2N=Cc3cccc[n]3->[Ru+2]<-[n]2c1
#2 0.01 ± 0.02
Cc1ccc(C(C)C)[cH]2->[Ru+2]3(<-[cH]12)<-[N](=Cc1cccc[n]->31)c1ncc(Br)cc1Br
#2 0.00 ± 0.00
Brc1cc(Br)c2N=Cc3cccc[n]3->[Ru+2]<-[n]2c1
#3 0.00 ± 0.00
Brc1cc(Br)c2N=Cc3cccc[n]3->[Ru+2]<-[n]2c1
#3 0.00 ± 0.00
Brc1cc(Br)c2N=Cc3cccc[n]3->[Ru+2]<-[n]2c1
#3 0.00 ± 0.00
Brc1cc(Br)c2N=Cc3cccc[n]3->[Ru+2]<-[n]2c1
#3 0.00 ± 0.00
Brc1cc(Br)c2N=Cc3cccc[n]3->[Ru+2]<-[n]2c1
#3 0.00 ± 0.00
Brc1cc(Br)c2N=Cc3cccc[n]3->[Ru+2]<-[n]2c1
#3 0.00 ± 0.00
Brc1cc(Br)c2N=Cc3cccc[n]3->[Ru+2]<-[n]2c1